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If x and y are positive integers, what is the remainder when

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If x and y are positive integers, what is the remainder when [#permalink] New post 20 Mar 2012, 00:40
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If x and y are positive integers, what is the remainder when 10^x +y is divided by 3?

(1) x=5
(2) y=2

I guessed on this question and I was lucky to get it right admittedly. I want to know the appropriate or possible appropriate method to use in solving this problem.
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Re: If x and y are positive integers... [#permalink] New post 20 Mar 2012, 00:51
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If x and y are positive integers, what is the remainder when 10^x +y is divided by 3?

Since, the sum of the digits of 10^x is always 1 then the remainders when 10^x+y is divided by 3 is only dependant on the value of the number added to 10^x, so on y. If y is a multiple of 3 then 10^x+y will yield the remainder of 1 (since the sum of the digits of 10^x+y will be one more than a multiple of 3), if y is one more than a multiple of 3 then 10^x+y will yield the remainder of 2 and finally if y is two more than a multiple of 3 then 10^x+y will yield the remainder of 0,

(1) x=5. Not sufficient.
(2) y=2. Sufficient.

Answer: B.
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Re: If x and y are positive integers, what is the remainder when [#permalink] New post 09 May 2012, 14:07
So the question should be ((10^x)+y)/3?

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Re: If x and y are positive integers, what is the remainder when [#permalink] New post 09 May 2012, 14:57
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Re: If x and y are positive integers, what is the remainder when [#permalink] New post 05 Sep 2012, 03:17
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The OG explanations sometimes really baffle me; I reached the solution simply by realizing that it did not matter what power the 10 was to be elevated to, and to know the value of y was sufficient; just like Bunuel explained above. The OG explanation should not be the primary route, in my opinion.
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Re: If x and y are positive integers, what is the remainder when   [#permalink] 05 Sep 2012, 03:17
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