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1. leads to x = 2by + 4, it is insufficient however, take y < 4 with 2y > 4

2. lead to x+y = cy + 4 => x = (c+1) y + 4 in this case because 4 is said to be reminder after dividing by y, y cannot be less then 4.

Thus 2 is sufficient, 1 is not.

I did get answer B. But I approached it be inserting numbers, which took a while. I did not follow the above explanation. Can you please restate how 2 is sufficient from above.

I did get answer B. But I approached it be inserting numbers, which took a while. I did not follow the above explanation. Can you please restate how 2 is sufficient from above.

2 means that x can be represented in the form a*y + r and 0 <= (r = 4) < y, those two together mean that r=4 will be a reminder x/y

Last edited by Tyr on 22 Apr 2005, 15:57, edited 1 time in total.

Re: What is the reminder for x/y? [#permalink]
11 Jun 2012, 04:19

manulath wrote:

Statement 1 is insuff. x=4/3, y=3/2, x=8, y=9.......

Statement 2: (x+y)/y has remainder as 4 this can be written as.......(x/y + 1) as 1 is a whole number the fraction comes from x/y.......which is 4

Hence SUFF.

Ans B

Hey there, Can u please explain concept behind statement 2 : "as 1 is a whole number the fraction comes from x/y.......which is 4" How do you know x/y will always give same remainder?

Re: What is the reminder for x/y? [#permalink]
11 Jun 2012, 06:33

2

This post received KUDOS

kuttingchai wrote:

manulath wrote:

Statement 1 is insuff. x=4/3, y=3/2, x=8, y=9.......

Statement 2: (x+y)/y has remainder as 4 this can be written as.......(x/y + 1) as 1 is a whole number the fraction comes from x/y.......which is 4

Hence SUFF.

Ans B

Hey there, Can u please explain concept behind statement 2 : "as 1 is a whole number the fraction comes from x/y.......which is 4" How do you know x/y will always give same remainder?

The idea used here is that any number can be written in form of a fraction. (Integers can be the number divided by 1)

eg 0.111 = 111/1000

9.99 = 999/100 = 9 + 99/100 = 9 + 0.99

There are two numbers = x and y Let x be a*y + c (where a and c are integers)

What is the remainder of x/y?

x/y = (a*y + c)/y = a + c/y We see that c is the remainder and a is quotient. We have to find c

Given (x + y) /y has remainder as 4 (x+y)/y => (a*y + c + y)/y => a + c/y + 1 => The quotient is (a+1) and remainder is c. (Already given as 4)

Any whole number will be added to the quotient and not remainder.

Re: What is the reminder for x/y? [#permalink]
12 Oct 2013, 06:02

raviatreya wrote:

What is the reminder for x/y?

(1) Reminder for x/(2y) is 4. (2) Reminder for (x+y)/y is 4.

Answer is (B) this is pretty straightforward.

Statement 1: x= 2y+4 and we also know that we want to find x=4+r so if we equal both we get y+4 = r. We don't know 'y' so not good enough Statement 2: x+y/y remainder is 4. y/y has no remainder so x/y will have remainder 4.