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# If x and y are positive, is x^3 > y? (1) square root

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If x and y are positive, is x^3 > y? (1) square root [#permalink]

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16 Oct 2004, 05:59
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If x and y are positive, is x^3 > y?

(1) square root (x)> y
(2) x > y
Manager
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16 Oct 2004, 06:32
My answer will be E - both not sufficient
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16 Oct 2004, 09:25
1. sqrt(X) >Y. Suff. let sqrt(X) = 4. => X=2 =>X^3 = 8. If 4 is > y then 8 is surely > Y.

2. X>Y. let X=2. if 2>Y then X63 is 8 will surely be > than Y. Suff.

D.

Note: X and Y are positive.
Joined: 31 Dec 1969
Location: Russian Federation
Concentration: Technology, Entrepreneurship
GMAT 1: 710 Q49 V0
GMAT 2: 700 Q V
GMAT 3: 740 Q40 V50
GMAT 4: 700 Q48 V38
GMAT 5: 710 Q45 V41
GMAT 6: 680 Q47 V36
GMAT 7: Q42 V44
GMAT 8: Q42 V44
GMAT 9: 740 Q49 V42
GMAT 10: 740 Q V
GMAT 11: 500 Q47 V33
GMAT 12: 670 Q V
WE: Engineering (Manufacturing)
Followers: 0

Kudos [?]: 202 [0], given: 102358

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16 Oct 2004, 09:26
1. sqrt(X) >Y. Suff. let sqrt(X) = 4. => X=2 =>X^3 = 8. If 4 is > y then 8 is surely > Y.

2. X>Y. let X=2. if 2>Y then X^3 is 8 will surely be > than Y. Suff.

D.

Note: X and Y are positive.
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16 Oct 2004, 10:18
consider a case of fraction
(1) square root (x)> y , this does not mean that x^3 will also be greater than y.

(2) x > y. Same explanation here.
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16 Oct 2004, 10:24
My answer is E

If x = 1/9, and y = 1/10

square root of 1/9 = 1/3 which is > (1/10)

1/9 > 1/ 10

but 1/9 ^ 3 = 1/729 which is less than 1/82

so (1) and (2) are insufficient
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16 Oct 2004, 10:48
Agree E. considering fractions is key.
16 Oct 2004, 10:48
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# If x and y are positive, is x^3 > y? (1) square root

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