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If x and y are positive, is x/y greater than 1?

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If x and y are positive, is x/y greater than 1? [#permalink]

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If x and y are positive, is x/y greater than 1?

(1) xy > 1
(2) x-y > 1
[Reveal] Spoiler: OA

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Re: If x and y are integers, is x/y greater than 1 ? [#permalink]

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New post 29 Apr 2012, 05:15
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monir6000 wrote:
If x and y are integers, is x/y greater than 1 ?

(1) xy > 1
(2) x – y > 0


ORIGINAL QUESTION READS:

If x and y are positive, is x/y greater than 1?

Is \(\frac{x}{y}>1\)? --> as given that \(y\) is positive we can safely multiply boith parts of inequality by it --> so the question becomes "is \(x>y\)?" OR: is \(x-y>0\)?

(1) \(xy>1\) --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) \(x-y>1\) --> \(x>y+1\) --> as \(x\) is more than \(y\) plus 1 then it's obviously more than just \(y\) alone: \(x>y\). Sufficient.
Or: as \(x-y>1\) then \(x-y\) is obviously more than zero --> \(x-y>1>0\). Sufficient.

Answer: B.
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Re: If x and y are integers, is x/y greater than 1 ? [#permalink]

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New post 22 Dec 2012, 05:29
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megafan wrote:
Bunuel wrote:
monir6000 wrote:
If x and y are integers, is x/y greater than 1 ?

(1) xy > 1
(2) x – y > 0


ORIGINAL QUESTION READS:

If x and y are positive, is x/y greater than 1?

Is \(\frac{x}{y}>1\)? --> as given that \(y\) is positive we can safely multiply boith parts of inequality by it --> so the question becomes "is \(x>y\)?" OR: is \(x-y>0\)?

(1) \(xy>1\) --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) \(x-y>1\) --> \(x>y+1\) --> as \(x\) is more than \(y\) plus 1 then it's obviously more than just \(y\) alone: \(x>y\). Sufficient.
Or: as \(x-y>1\) then \(x-y\) is obviously more than zero --> \(x-y>1>0\). Sufficient.

Answer: B.


Slight correction, even though your answer and your reasoning are correct, is that your reasoning for 2 does not address the question mentioned -- again, it's still correct, but want to make sure it talks about the question. It should be \(x-y>0\) not \(x-y>1\)


The question posted by monir6000 has typos. Again:

ORIGINAL QUESTION READS:
If x and y are positive, is x/y greater than 1?
(1) xy>1
(2) x-y>1
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Re: If x and y are ingeger, is x/y greater than 1 ? [#permalink]

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New post 28 Apr 2012, 22:04
C is the answer.
1. xy=1 says nothing about which is greater, x or y.
So insufficient.
2. x-y>O i.e. X>Y
So if x and y are integars
so x/y >1 but if x is negative or y is negative.? It can be less than 1 also. So
Insufficient.
1+2
X and y are of same sign by xy>1 and x>y so sufficient.

C is right.

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DS [#permalink]

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New post 29 Apr 2012, 05:09
If x and y are positive, is x/Y greater than 1 ?
(1) xy > 1
(2) x – y > 0
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Re: If x and y are integers, is x/y greater than 1 ? [#permalink]

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New post 21 Dec 2012, 19:54
Bunuel wrote:
monir6000 wrote:
If x and y are integers, is x/y greater than 1 ?

(1) xy > 1
(2) x – y > 0


ORIGINAL QUESTION READS:

If x and y are positive, is x/y greater than 1?

Is \(\frac{x}{y}>1\)? --> as given that \(y\) is positive we can safely multiply boith parts of inequality by it --> so the question becomes "is \(x>y\)?" OR: is \(x-y>0\)?

(1) \(xy>1\) --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) \(x-y>1\) --> \(x>y+1\) --> as \(x\) is more than \(y\) plus 1 then it's obviously more than just \(y\) alone: \(x>y\). Sufficient.
Or: as \(x-y>1\) then \(x-y\) is obviously more than zero --> \(x-y>1>0\). Sufficient.

Answer: B.


Slight correction, even though your answer and your reasoning are correct, is that your reasoning for 2 does not address the question mentioned -- again, it's still correct, but want to make sure it talks about the question. It should be \(x-y>0\) not \(x-y>1\)
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Re: If x and y are positive, is x/y greater than 1? [#permalink]

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New post 17 Aug 2014, 21:14
Referring to the same question.
1) The statement is insufficient without a doubt
2) x-y>0, in case x is 7 and y is 3. But if y is -3, then the solution will be 7-(-3)=10 which is greater than 10.

But in case y is negative, then x/y, will not be greater than 1.

Need some help here - Am i missing something?
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Re: If x and y are positive, is x/y greater than 1? [#permalink]

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New post 18 Aug 2014, 02:58
Expert's post
omerqureshi wrote:
Referring to the same question.
1) The statement is insufficient without a doubt
2) x-y>0, in case x is 7 and y is 3. But if y is -3, then the solution will be 7-(-3)=10 which is greater than 10.

But in case y is negative, then x/y, will not be greater than 1.

Need some help here - Am i missing something?


The stem says: if x and y are positive...
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: If x and y are positive, is x/y greater than 1? [#permalink]

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Re: If x and y are positive, is x/y greater than 1?   [#permalink] 26 Dec 2015, 16:24
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