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If x and y are positive real numbers, is x > y?

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If x and y are positive real numbers, is x > y? [#permalink] New post 15 Aug 2009, 23:47
00:00
A
B
C
D
E

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  5% (low)

Question Stats:

20% (02:25) correct 80% (01:23) wrong based on 12 sessions
10)If x and y are positive real numbers, is x > y?

i) x^3/y < 1

ii) (x^1/3)/y < 1
Senior Manager
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Re: is x > y? [#permalink] New post 16 Aug 2009, 01:59
IMO A
stmt1:
x^3/y < 1 , since x and y are positive.

x^3 < y => x<y.
suffi

stmt2:
(X^(1/3)) / y < 1
x^ (1/3) < y
taking cube on both sides
x < y^3
when x =1, y =2, x<y and x<y^3.
when x=4, y=2, x>y and x<y^3.
insuffi
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Re: is x > y? [#permalink] New post 16 Aug 2009, 04:07
yezz wrote:
10)If x and y are positive real numbers, is x > y?

i) x^3/y < 1

ii) (x^1/3)/y < 1


E.
stmt 1:
x^3<y
We can take x=1/2, y=1/2, then x=y.
We can take x=2, y=10 then x<y.
Insufficient

stmt 2:
x<y^3.
If y=2, x=2 then x=y.
If y=2, x=4 then x>y.
Insufficient

Combining, we have the same problem. Insufficient.
Senior Manager
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Re: is x > y? [#permalink] New post 16 Aug 2009, 06:20
Economist wrote:
We can take x=1/2, y=1/2, then x=y.
We can take x=2, y=10 then x<y.
Insufficient


good point... i forgot to consider the rational part of the real number... it is E , i agree.
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Re: is x > y? [#permalink] New post 02 Sep 2009, 16:53
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What does real number mean. GMAC never uses such terminology as far as I know.
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Re: is x > y? [#permalink] New post 31 Jul 2011, 11:38
Re: is x > y?   [#permalink] 31 Jul 2011, 11:38
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If x and y are positive real numbers, is x > y?

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