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If x and y are selected from 2, 3, 4, 5 and 6. What is the

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New post 26 Apr 2006, 02:44
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If x and y are selected from 2, 3, 4, 5 and 6. What is the probability that x*y is divisible by 4?
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New post 26 Apr 2006, 03:20
It's divisible by 4 if the product is a multiple of 4

Possiblilites = 2*4, 2*6, 3*4, 4*6 --> 4 ways

Number of ways to pick any 2 numbers = 5C2 = 10 ways

P = 4/10 = 2/5
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New post 26 Apr 2006, 06:34
what about 5*4

same way to solve, just add one case.

so 5/10 or 1/2
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New post 26 Apr 2006, 12:29
First of all, the answer depends on whether x and y can be the same
number. I don't think that the question is clear in regard to that.

If x and y can be the same:

{2,2}
{2,4}
{2,6}
{3,4}
{4,2}
{4,3}
{4,4}
{4,5}
{4,6}
{5,4}
{6,2}
{6,4}
{6,6}

So 13/25.

==

If x and y can't be the same:

{2,4}
{2,6}
{3,4}
{4,2}
{4,3}
{4,5}
{4,6}
{5,4}
{6,2}
{6,4}

So 10/20 = 1/2.
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New post 27 Apr 2006, 07:38
1/2

Total 5C2 = 10

Favourable possibilities = 2*4; 2*6; 3*4; 4*5; 4*6.
5/10=1/2.
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New post 28 Apr 2006, 05:25
total no.of ways for selecting xand y = 5C2 = 10

divisible by 4... donein two ways

1. multiplication of two een numbers = 3C2 = 3
2. multiplication of an odd number by 4 = 1.2C1 = 2

therefore 5/10 = 1/2
  [#permalink] 28 Apr 2006, 05:25
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