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stmt 1: x and y can be anything...(4,8) (5,7)....(-12,24). stmt 2: y = 2x, again we can have (4,8) (5,10)...since 6 is not necessarily the midpoint of the line segment under consideration.

combining, 6+c = y = 2x, 6-c=x adding these two equations, we get 12 = 3x => x = 4, y=8. This is the only possibility that satisfies both conditions.

However, if stmt 2 was something like: |y| = |2x|, then answer would have been E.

I have to disagree with C. The answer to the question must be A.

If x and y are two points on the number line what is the value of x + y?

(1) 6 is halfway between x and y. On the GMAT we often see such statement and it can ALWAYS be expressed algebraically as \(6=\frac{x+y}{2}\) --> \(x+y=12\). Remember we are asked to determine the value of \(x+y\) not \(x\) and \(y\). Sufficient.

If x and y are two points on the number line what is the [#permalink]
23 Apr 2012, 21:20

If x and y are points on the number line, what is the value of x + y ? (1) 6 is halfway between x and y. (2) y = 2x

Ans: A When we say 6 is midway between x and y it means among x and y one number is 6 + m and other is 6 - m thus sum of x and y is (6+m)+(6-m) thus 12 irrespective of the value of m..

Re: If x and y are two points on the number line what is the [#permalink]
20 Sep 2014, 17:22

Question is asking X+Y =>

isn't below always 12? ==< answer should be A. stmt 1: x and y can be anything...(4,8) (5,7)....(-12,24).

Economist wrote:

IMO C.

stmt 1: x and y can be anything...(4,8) (5,7)....(-12,24). stmt 2: y = 2x, again we can have (4,8) (5,10)...since 6 is not necessarily the midpoint of the line segment under consideration.

combining, 6+c = y = 2x, 6-c=x adding these two equations, we get 12 = 3x => x = 4, y=8. This is the only possibility that satisfies both conditions.

However, if stmt 2 was something like: |y| = |2x|, then answer would have been E.

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