If x and y are +ve, is y > 2? 1. x > 2y 22. x < y+2 : DS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 19 Jan 2017, 15:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x and y are +ve, is y > 2? 1. x > 2y 22. x < y+2

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Senior Manager
Joined: 07 Oct 2003
Posts: 353
Location: Manhattan
Followers: 2

Kudos [?]: 20 [0], given: 0

If x and y are +ve, is y > 2? 1. x > 2y 22. x < y+2 [#permalink]

### Show Tags

18 Aug 2004, 15:11
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x and y are +ve, is y > 2?
1. x > 2y
22. x < y+2
Senior Manager
Joined: 25 Jul 2004
Posts: 273
Followers: 1

Kudos [?]: 10 [0], given: 0

### Show Tags

18 Aug 2004, 15:21
I would say C.

Combining
x > 2y
And
x < y+2

we get 2Y < Y + 2
subtracting Y we get
Y < 2
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5062
Location: Singapore
Followers: 30

Kudos [?]: 358 [0], given: 0

### Show Tags

18 Aug 2004, 18:53
from 1, x/2 > y. sufficient. we know x is positive, so x can take values 1,2,3,4,... etc
so y will always be less than values 1/2,1/3,1/4,1/5.. etc depending on what value x takes on.
so from 1, we know y >2 will never happen

from 2, x-2 < y, for 2 < y, x have to be 4 and above. but we only know x and y are positive, and x could be 1. so 2 is insufficient.

(a) is the answer
Director
Joined: 13 Nov 2003
Posts: 964
Location: Florida
Followers: 1

Kudos [?]: 127 [0], given: 0

### Show Tags

18 Aug 2004, 19:26
C for me too. I key'ed in the numbers, only for y<2 both statements hold good.

Sig, I like your reasoning
Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India
Followers: 1

Kudos [?]: 37 [0], given: 0

### Show Tags

18 Aug 2004, 19:30
Hello wilfred

You have mentioned ....

Quote:
from 1, x/2 > y. sufficient. we know x is positive, so x can take values 1,2,3,4,... etc
so y will always be less than values 1/2,1/3,1/4,1/5.. etc depending on what value x takes on.
so from 1, we know y >2 will never happen

This is not correct.

X>2y ---> if x is 1 then y is 1/2, if x is 10, then y=5, Hence this does not stand good.

C is the answer. Combing both we know that, Y is less than 2.
_________________

Giving another SHOT

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5062
Location: Singapore
Followers: 30

Kudos [?]: 358 [0], given: 0

### Show Tags

18 Aug 2004, 19:31
ah !! i'm always prone to these errors... thanks for pointing them out carsen !
18 Aug 2004, 19:31
Display posts from previous: Sort by

# If x and y are +ve, is y > 2? 1. x > 2y 22. x < y+2

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.