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If x and y represent digits of a two digit number divisible

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VP
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If x and y represent digits of a two digit number divisible [#permalink] New post 27 Jan 2008, 10:35
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please
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Re: integers [#permalink] New post 27 Jan 2008, 16:58
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

Some explanation of choice 2 please


1. Sum of the digits is a multiple of 18

Sum of the digits has to be 18 / 36 / 54 etc...
The smallest # whose sum of digits is 18 is 99. Hence # > 50. Sufficient.

2. Product of the digits is a multiple of 9
Prod of digits can be 9, 18, 27, 36.....

9 - 19 or 91
18 - 36 or 63 or 29 or 92
27 - 39 or 93
.
.
.

So insuff..
I would answer A.

Whats OA ?
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Last edited by suntaurian on 17 Feb 2008, 22:38, edited 2 times in total.
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Re: integers [#permalink] New post 27 Jan 2008, 19:12
Expert's post
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please



Question and test number please.
This helps us improve our questions and explanations.
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Re: integers [#permalink] New post 08 Feb 2008, 03:45
bb wrote:
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please



Question and test number please.
This helps us improve our questions and explanations.


http://gmatclub.com/tests/m02#q31
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Re: integers [#permalink] New post 08 Feb 2008, 10:54
I am confused. I used the same logic. But shouldn't the answer be "A"?
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Re: integers [#permalink] New post 08 Feb 2008, 11:08
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please


obviously x + y <= 18 because x and y are digits

1) sufficient -> x = 9, y = 9; 99 exceeds 50.
2) 3 options 19, 33, 91 - only 33 is divisible by 3 -> 33 < 50 -> sufficient

D is the answer
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Re: integers [#permalink] New post 08 Feb 2008, 11:43
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please


1. Only two digit number that adds up to be a multiple of 18 is 99. SUFFICIENT
2. 19, 33 and 19 all have products that = 9, but it just says multiple of nine. This means 29, 92, 36 and 63 are all included as well (among others). INSUFFICIENT

Answer A

(I just checked the question in the test and the OA is A)
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Re: integers [#permalink] New post 08 Feb 2008, 11:51
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please


OA is B??? are you sure???

1: only number that could fulfill these requirements is 99. Suff

2: we can have 33 --> 3*3 or 99 --> 9*9

So i dunno bout this one.
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Re: integers [#permalink] New post 17 Feb 2008, 22:14
GMATBLACKBELT wrote:
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please


OA is B??? are you sure???

1: only number that could fulfill these requirements is 99. Suff

2: we can have 33 --> 3*3 or 99 --> 9*9

So i dunno bout this one.


I bag your pardon. OA is A
Re: integers   [#permalink] 17 Feb 2008, 22:14
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