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# If x and y represent digits of a two digit number divisible

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VP
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If x and y represent digits of a two digit number divisible [#permalink]

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27 Jan 2008, 10:35
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please
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27 Jan 2008, 16:58
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

Some explanation of choice 2 please

1. Sum of the digits is a multiple of 18

Sum of the digits has to be 18 / 36 / 54 etc...
The smallest # whose sum of digits is 18 is 99. Hence # > 50. Sufficient.

2. Product of the digits is a multiple of 9
Prod of digits can be 9, 18, 27, 36.....

9 - 19 or 91
18 - 36 or 63 or 29 or 92
27 - 39 or 93
.
.
.

So insuff..

Whats OA ?
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Last edited by suntaurian on 17 Feb 2008, 22:38, edited 2 times in total.
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27 Jan 2008, 19:12
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please

This helps us improve our questions and explanations.
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08 Feb 2008, 03:45
bb wrote:
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please

This helps us improve our questions and explanations.

http://gmatclub.com/tests/m02#q31
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08 Feb 2008, 10:54
I am confused. I used the same logic. But shouldn't the answer be "A"?
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08 Feb 2008, 11:08
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please

obviously x + y <= 18 because x and y are digits

1) sufficient -> x = 9, y = 9; 99 exceeds 50.
2) 3 options 19, 33, 91 - only 33 is divisible by 3 -> 33 < 50 -> sufficient

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08 Feb 2008, 11:43
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please

1. Only two digit number that adds up to be a multiple of 18 is 99. SUFFICIENT
2. 19, 33 and 19 all have products that = 9, but it just says multiple of nine. This means 29, 92, 36 and 63 are all included as well (among others). INSUFFICIENT

(I just checked the question in the test and the OA is A)
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08 Feb 2008, 11:51
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please

OA is B??? are you sure???

1: only number that could fulfill these requirements is 99. Suff

2: we can have 33 --> 3*3 or 99 --> 9*9

So i dunno bout this one.
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17 Feb 2008, 22:14
GMATBLACKBELT wrote:
marcodonzelli wrote:
If x and y represent digits of a two digit number divisible by 3, is the two digit number less than 50?

1. Sum of the digits is a multiple of 18
2. Product of the digits is a multiple of 9

Some explanation of choice 2 please

OA is B??? are you sure???

1: only number that could fulfill these requirements is 99. Suff

2: we can have 33 --> 3*3 or 99 --> 9*9

So i dunno bout this one.

I bag your pardon. OA is A
Re: integers   [#permalink] 17 Feb 2008, 22:14
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