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If X does not equal 0, x= (4xy - 4y^2)^(1/2) then in terms

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If X does not equal 0, x= (4xy - 4y^2)^(1/2) then in terms [#permalink] New post 23 May 2007, 16:09
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If X does not equal 0, x= (4xy - 4y^2)^(1/2) then in terms of y, x =

how do i solve this algebraically?

x^2 = 4xy - 4y^2
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Re: PS #17 [#permalink] New post 23 May 2007, 17:05
bmwhype2 wrote:
If X does not equal 0, x= (4xy - 4y^2)^(1/2) then in terms of y, x =

how do i solve this algebraically?

x^2 = 4xy - 4y^2


x^2 = 4xy - 4y^2

get everything on one side:

0 = x^2 - 4xy + 4y^2

simplify

0 = (x - 2y)^2

sqrt both sides it to eliminate the square on the right since sqrt of 0 = 0

0 = x - 2y

x = 2y
Re: PS #17   [#permalink] 23 May 2007, 17:05
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If X does not equal 0, x= (4xy - 4y^2)^(1/2) then in terms

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