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# If x does not equal to &#1090;&#1040;&#1059;y, is

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Manager
Joined: 01 Sep 2003
Posts: 73
Location: NYC
Followers: 0

Kudos [?]: 1 [0], given: 0

If x does not equal to &#1090;&#1040;&#1059;y, is [#permalink]  14 Dec 2003, 18:09
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If x does not equal to тАУy, is (x-y)/(x+y) > 1?

a. x>0
b. y<0

But I went like this to solve the problem:

: (x-y)/(x+y) > 1
: (x-y)>(x+y)
: x-y>x+y
: -y>y

Meaning тАЬyтАЭ is a negative number, thus I picked B.
Why is this wrong?
Director
Joined: 13 Nov 2003
Posts: 971
Location: Florida
Followers: 1

Kudos [?]: 31 [0], given: 0

Re: DS [#permalink]  14 Dec 2003, 18:19
ftoor wrote:
If x does not equal to тАУy, is (x-y)/(x+y) > 1?

a. x>0
b. y<0

But I went like this to solve the problem:

: (x-y)/(x+y) > 1
: (x-y)>(x+y)
: x-y>x+y
: -y>y

Meaning тАЬyтАЭ is a negative number, thus I picked B.
Why is this wrong?

I wud have thot the same, but when you plug in the values you will know the reason. try:
(X,Y): (0,-1), (2,-1), (-2,-1)
Manager
Joined: 06 Jun 2003
Posts: 59
Followers: 1

Kudos [?]: 1 [0], given: 0

One way of looking at this is : the inequality direction (> or <) may change depending on the sign (+ or -) of x+y .. given both A and B we still wouldn't know what the sign would be ..
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