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If x is a positive integer, is the remainder 0 when 3^x + 1

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Manager
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If x is a positive integer, is the remainder 0 when 3^x + 1 [#permalink]

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New post 11 Nov 2008, 13:59
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x is a positive integer, is the remainder 0 when 3^x + 1 is divided by 10?
(1) x = 4n + 2, where n is a positive integer.
(2) x > 4

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
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Re: remainder--27 [#permalink]

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New post 12 Nov 2008, 01:10
3^x +1 can be divided by 10 only when 3^x has unit digit of 9

stmt 1: I try to find x by using n=1,2,3, it shows that 3^x are all give unit digit 9 which can be divided by 10 >>> suff

stmt 2: n can be any # --> not suff

IMO A
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Re: remainder--27 [#permalink]

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New post 12 Nov 2008, 01:21
Jcpenny wrote:
If x is a positive integer, is the remainder 0 when 3^x + 1 is divided by 10?
(1) x = 4n + 2, where n is a positive integer.
(2) x > 4

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


(1) 3^x + 1 = 3^(4n + 2) + 1 = 9*(3^4)^n + 1 = 9 * (81)^n + 1

as 81 ^n always has the last digit = 1 (with all n) => 9 * (81)^n has the last digit = 9

=> 9 * (81)^n + 1 is divisible by 10

(1) suff
Re: remainder--27   [#permalink] 12 Nov 2008, 01:21
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If x is a positive integer, is the remainder 0 when 3^x + 1

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