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VP
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If x is a positive integer, is the remainder 0 when 3x + 1 [#permalink]
19 Jan 2008, 11:53
If x is a positive integer, is the remainder 0 when 3x + 1 is divided by 10? (1) x = 4n + 2, where n is a positive integer. (2) x > 4
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Director
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Basically is X an integer with 3 in the units digit: 3, 13, 23, 33, etc
1. Multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32 etc. None of these numbers + 2 will give us 3 in the units digit SUFFICIENT 2. x>4 doesn't help us because X could be 12 (not work) or 13 (works) INSUFFICIENT
taken together we learn nothing new either
Answer A
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SVP
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should be A.
You can see from A that 4n+2 always gives an even number, and plugging the result into 3x+1 always gives an odd number. All multiples of ten are even numbers, so you'll never have a perfect multiple of 10.
With B, you can have n=5 which doesnt give a remainder of 0, or n=13, which does. Insuff.
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Senior Manager
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Should be A as explained by eschn3am
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CEO
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marcodonzelli wrote: If x is a positive integer, is the remainder 0 when 3x + 1 is divided by 10? (1) x = 4n + 2, where n is a positive integer. (2) x > 4 1: Suff. Notice that X must be even. b/c 4(n) is even and 2 is even and E+E= even. Also notice that only when x has a 3 in its units digit can 3x+1 be divisible by 10. Since E+E will never equal an odd. the remainder cannot be 0. 2: X can be 5 or 13.
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