If x is a positive integer, is (x+y) even?

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If x is a positive integer, is (x+y) even? [#permalink]

05 Aug 2012, 23:02

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If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1

Last edited by Bunuel on 06 Aug 2012, 00:42, edited 1 time in total.

Edited the question.

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Re: If x is a positive integer, is (x+y) even? [#permalink]

06 Aug 2012, 00:54

ananthpatri wrote:

If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1

(1) States K^{x+y}=1. If K = 1, x + y can be odd or even. Not sufficient.

(2) Nothing about x + y. Not sufficient.

(1) and (2) together: Sufficient, because necessarily x + y = 0.

Answer C.
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Re: If x is a positive integer, is (x+y) even? [#permalink]

06 Aug 2012, 01:03

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EvaJager wrote:

ananthpatri wrote:

If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1

(1) States K^{x+y}=1. If K = 1, x + y can be odd or even. Not sufficient.

(2) Nothing about x + y. Not sufficient.

(1) and (2) together: Sufficient, because necessarily x + y = 0.

Answer C.

x+y is not necessarily zero. If k=-1, then x+y can be ANY even number.
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Re: If x is a positive integer, is (x+y) even? [#permalink]

06 Aug 2012, 01:08

Bunuel wrote:

EvaJager wrote:

ananthpatri wrote:

If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1

(1) States K^{x+y}=1. If K = 1, x + y can be odd or even. Not sufficient.

(2) Nothing about x + y. Not sufficient.

(1) and (2) together: Sufficient, because necessarily x + y = 0.

Answer C.

x+y is not necessarily zero. If k=-1, then x+y can be ANY even number.

You are absolutely right. Nothing stated about K! At least the answer is still C.
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Re: If x is a positive integer, is (x+y) even? [#permalink]

06 Aug 2012, 01:09

Thanks for the answer.

Re: If x is a positive integer, is (x+y) even? [#permalink] 06 Aug 2012, 01:09

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If x is a positive integer, is (x+y) even?

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If x is a positive integer, is (x+y) even?

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