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If x is a positive integer, is (x+y) even?

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If x is a positive integer, is (x+y) even? [#permalink] New post 05 Aug 2012, 22:02
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If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1

Last edited by Bunuel on 05 Aug 2012, 23:42, edited 1 time in total.
Edited the question.
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Re: If x is a positive integer, is (x+y) even? [#permalink] New post 05 Aug 2012, 23:54
ananthpatri wrote:
If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1


(1) States K^{x+y}=1. If K = 1, x + y can be odd or even. Not sufficient.

(2) Nothing about x + y. Not sufficient.

(1) and (2) together: Sufficient, because necessarily x + y = 0.

Answer C.
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Re: If x is a positive integer, is (x+y) even? [#permalink] New post 06 Aug 2012, 00:03
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EvaJager wrote:
ananthpatri wrote:
If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1


(1) States K^{x+y}=1. If K = 1, x + y can be odd or even. Not sufficient.

(2) Nothing about x + y. Not sufficient.

(1) and (2) together: Sufficient, because necessarily x + y = 0.

Answer C.


x+y is not necessarily zero. If k=-1, then x+y can be ANY even number.
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Director
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Re: If x is a positive integer, is (x+y) even? [#permalink] New post 06 Aug 2012, 00:08
Bunuel wrote:
EvaJager wrote:
ananthpatri wrote:
If x is a positive integer, is (x+y) even?

(1) K^x*K^y =1
(2) K is not equal to 1


(1) States K^{x+y}=1. If K = 1, x + y can be odd or even. Not sufficient.

(2) Nothing about x + y. Not sufficient.

(1) and (2) together: Sufficient, because necessarily x + y = 0.

Answer C.


x+y is not necessarily zero. If k=-1, then x+y can be ANY even number.


You are absolutely right. Nothing stated about K! At least the answer is still C.
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Re: If x is a positive integer, is (x+y) even? [#permalink] New post 06 Aug 2012, 00:09
Thanks for the answer.
Re: If x is a positive integer, is (x+y) even?   [#permalink] 06 Aug 2012, 00:09
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