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If x is a positive integer, is y^2 (x^3 - x + 1)

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VP
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If x is a positive integer, is y^2 (x^3 - x + 1) [#permalink] New post 01 Oct 2008, 23:00
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions
If x is a positive integer, is y^2 (x^3 - x + 1) > 75?

1. y > 1
2. (x-1)^2=16
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Re: DS - Inequality [#permalink] New post 01 Oct 2008, 23:13
(1). y > 1

y = 2, x = 0 -> not satisfy
y = 10, x = 0 -> satisfy

(1) insufficient

(2) (x-1)^2=16, x positive negative => x = 5

x = 5, y = 0 - > not satify
x = 5, y = 1 -> satisfy

=> (2) insufficient

(1) & (2), x = 5, y > 1

y^2 (x^3 - x + 1 ) > = x^3 - x + 1 > = 121 > 75

sufficient

So the answer is C
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Re: DS - Inequality [#permalink] New post 02 Oct 2008, 00:37
lylya4 wrote:
(1). y > 1

y = 2, x = 0 -> not satisfy
y = 10, x = 0 -> satisfy

(1) insufficient

(2) (x-1)^2=16, x positive negative => x = 5

x = 5, y = 0 - > not satify
x = 5, y = 1 -> satisfy

=> (2) insufficient

(1) & (2), x = 5, y > 1

y^2 (x^3 - x + 1 ) > = x^3 - x + 1 > = 121 > 75

sufficient

So the answer is C

IMO E
x=-3 or 5 with x=-3 we get the opposite answer hence INSUFFI
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Re: DS - Inequality [#permalink] New post 02 Oct 2008, 01:24
Manager,
What is the correct answer to your problem?

My take is that is E cos
1- doesn't give you a value for x
2- x=5 or x = -3 , doesn't give a value for y

Both together, the statement is correct only if x = 5, but for x=-3, it's not valid. so it's E
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Re: DS - Inequality [#permalink] New post 02 Oct 2008, 01:26
let me correct myself. i didn't see that is says that x is a positive integer, so it's C
Re: DS - Inequality   [#permalink] 02 Oct 2008, 01:26
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