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if Z is closer to 10, then it will pull closer to 10, while if x is furhter apart the avg is going to pull closer to X....

say if X is 5, then 10+5=15/2= 7.5

well we are told in I) that the Z is closer to 10 than to X...so

Z has to be greater than 7, cause if i z was say 7, it will be only 2 points away from 5 and 3 points away from 10...(1) tells us that z is closer to 10, than it is to X...so probably z=8 or 9 or something....

(II) x can be 1 then you will see the avg of 10 and x is 5.5, but z=5.

If z=9 and x=8, Average of X and 10 will be equal to 9 which is equal to z. The question clearly asks if z will be greater than the average of x and 10. So am not too sure if A is sufficient. If it were greater than or equal to then , your argument is correct.

If z=9 and x=8, Average of X and 10 will be equal to 9 which is equal to z. The question clearly asks if z will be greater than the average of x and 10. So am not too sure if A is sufficient. If it were greater than or equal to then , your argument is correct.

Hi Gmatsoon,

The statement 1) clearly says 'z is closer to 10 than to x' which means, you cannot consider z=9, x=8 as it would mean it is equidistant from x and 10 (by a value of 1). _________________