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Since y = 3x + 2, we know that dividing y by 3 will give a remainder of 2, hence it is not divisible by 3. Since anything that's divisible by 6 must be divisible by 3 and 2, this rules out 6 as a possible divisor of y.

Since y = 3x + 2, we know that dividing y by 3 will give a remainder of 2, hence it is not divisible by 3. Since anything that's divisible by 6 must be divisible by 3 and 2, this rules out 6 as a possible divisor of y.

Thoughts?

That logic seems to hold up! I came up with C plugging in numbers myself.

Actually I don't agree that it's easier to plug in numbers. It makes perfect sense that if a number isn't divisible by 3, it can't be divisible by 6. If I ran into this on the test, I would plug in numbers if I had plenty of time, but if I was pressed for time I'd confidently pick 6.