Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

stmnt 1 - minimum value which x can have is 7. so on arranging the numbers we have 1,3, x,8,12 where x can be b/w 3 and 8 if x=7 or x can be b/w 8 and 12 or after 12

if x = 7, avg of these numbers will be 6.2 and median is 7 so median is > avg . suff if x= 11, avg of these numbers will be 7 and median is 8 so median is > avg. suff if x= 100, avg of these numbers will be 24.8 and median is 8 so median is < avg. insuff

so stmnt1 is insuff

stmnt 2 - x is greater than median so x> 8 [ on arranging we get 1,3,8,x,12]

if x= 11, avg of these numbers will be 7 and median is 8 so median is > avg. suff if x= 100, avg of these numbers will be 24.8 and median is 8 so median is < avg. insuff

so stmnt 2 is insuff

taking together we have x>8 but still insuff. hence E

Would you mind elaborating more on your procedure? Thanks Cheers! J

x,3,1,12,8

If x is an integer, is the median of the 5 numbers shown greater than the average (arithmetic mean ) of the 5 numbers ?

We have a set: {1, 3, 8, 12, x} Question: is \(median>mean=\frac{x+1+3+8+12}{5}=\frac{x+24}{5}\)? Note that as we have odd (5) # of terms in the set then the median will be the middle term when arranged in ascending (or descending) order. So, if \(x\leq{3}\): {1, x, 3, 8, 12} then \(median=3\), if \(3<x\leq{8}\): {1, 3, x, 8, 12} then \(median=x\) and if \(x\geq{8}\): {1, 3, 8, x, 12} then \(median=8\).

(1) x>6. If \(x=7\) then the median will be 7 as well: {1, 3, 7, 8, 12} and mean will be \(mean=\frac{7+24}{5}=6.2\), so \(median=7>mean=6.2\) and the answer is YES BUT if \(x\) is very large number then the median will be 8: {1, 3, 8, 12, x=very large number} and mean will be more than median (for example if \(x=26\) then \(mean=\frac{26+24}{5}=10\), so \(median=8<10=mean\)) and the answer will be NO. Not sufficient.

(2) x is greater than the median of the 5 numbers --> so \(median=8\): now, if \(x=11\) then \(mean=\frac{11+24}{5}=7\), so \(median=8>7=mean\) and the answer is YES. Again it's easy to get answer NO with very large \(x\). Not sufficient.

(1)+(2) Again, x=11 and x=very large number give two diffrent answers to the question. Not sufficeint.

Low GPA MBA Acceptance Rate Analysis Many applicants worry about applying to business school if they have a low GPA. I analyzed the low GPA MBA acceptance rate at...

Every student has a predefined notion about a MBA degree:- hefty packages, good job opportunities, improvement in position and salaries but how many really know the journey of becoming...