If x is an integer, is x^3 even?

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If x is an integer, is x^3 even?

(1) 2x + 2 is even.

(2) 3x + 1 is even.


In the original condition, x^3=even? becomes x=even?. Then, there is 1 variable(x), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer.
For 1), 2x+2=even, 2x=even-2=even -> x=1 no, x=2 yes, which is not sufficient.
For 2), 3x+1=even, 3x=even-1=odd -> x=odd, which is no and sufficient.
Therefore, the answer is B.


 For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.

statement A--clearly insufficient had x been even or odd.
statement B means, 3x+1 is even, which means 3x is odd. This can only happen only if x is also odd.

Thus Sufficient.

The question is really...is X odd?

Statement 1

x could be odd or even

insuff

Statement 2

x must be odd

suff

B

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