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this is da kind of problem that takes you lots of time to solve if you do not know that 0ddx0dd=Odd so the last term must be odd also and for it comes -2

m will be surly divisible by 3 is k = 2
coz product of any three consecutive number will always be divisible by three.
1*2*3.....11*12*13........99*100*101

now que asks for what all valuse of k...m will be divisible by 3.
let assume that x and x-1 are not divisible by 3.else for any value to k….m will be divisible.
so we can have x-2 as value divisible by 3.
now subtracting or adding multiple 3 to x-2 will always give a numbers divisible by 3.

m will be surly divisible by 3 is k = 2 coz product of any three consecutive number will always be divisible by three. 1*2*3.....11*12*13........99*100*101

now que asks for what all valuse of k...m will be divisible by 3. let assume that x and x-1 are not divisible by 3.else for any value to k….m will be divisible. so we can have x-2 as value divisible by 3. now subtracting or adding multiple 3 to x-2 will always give a numbers divisible by 3.

x+1, x+4,x-5...so k can be 2,-4,-1,-5..but not -2

sorry to ask again

but I can't understand this question

if x=3 won't then the therm x*(x – 1)*(x – k) will be divisable by 3

squirrel,
from my previous post.....let assume that x and x-1 are not divisible by 3.else for any value to k….m will be divisible.

if we assume x or x-1 is divsible by 3 then que stands null and void.
as you rightly pointed that for any value of k ,term will be divisible.
hope this clears your doubt.

squirrel, from my previous post.....let assume that x and x-1 are not divisible by 3.else for any value to k….m will be divisible.

if we assume x or x-1 is divsible by 3 then que stands null and void. as you rightly pointed that for any value of k ,term will be divisible. hope this clears your doubt.

I dont think this is a valid GMAT question, cause as KS pointed K, K-1 could be divisible by 3...we just dont know..

it is a valid question. agreed x can be 3 but what if x is 5 ? the question asks about the whole expression ! and remember x * (x+1) * (x+2) can always be divided by 3.