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If x is an integer, what is the value of x? [#permalink]
02 Jun 2010, 17:43

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alokchaks wrote:

(1) The only perfect square in this range is 16. So √x can be +4 or -4. Not Sufficient. (2) The possible values for √x are 3 and 4. Not sufficient.

Combining (1) and (2), we get √x = 4. Ans C

Am I missing something?

Square root function cannot give negative result.

Any nonnegative real number has a unique non-negative square root called the principal square root and unless otherwise specified, the square root is generally taken to mean the principal square root.

When the GMAT provides the square root sign for an even root, such as \(\sqrt{x}\) or \(\sqrt[4]{x}\), then the only accepted answer is the positive root.

That is, \(\sqrt{25}=5\), NOT +5 or -5. In contrast, the equation \(x^2=25\) has TWO solutions, +5 and -5. Even roots have only non-negative value on the GMAT.

Odd roots will have the same sign as the base of the root. For example, \(\sqrt[3]{125} =5\) and \(\sqrt[3]{-64} =-4\). _________________

Re: If x is an integer, what is the value of x? [#permalink]
18 Sep 2014, 05:13

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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