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If x is equal to the sum of the even integers from m to n,

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Re: If x is equal to the sum of the even integers [#permalink] New post 22 Apr 2013, 23:06
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

71% (01:54) correct 29% (00:43) wrong based on 35 sessions
the answer should be C.......

please correct me if i am wrong....
[Reveal] Spoiler: OA
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Re: If x is equal to the sum of the even integers [#permalink] New post 22 Apr 2013, 23:14
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Option A.

First term in the series is m and last number is n. total number of terms(for both inclusive) = (n-m)/2 +1
Avg of first and last terms =(m+n)/2.

Sum of the terms = avg * number of terms.
((m+n)/2) *((n-m)/2 +1)
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Re: If x is equal to the sum of the even integers [#permalink] New post 23 Apr 2013, 01:45
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Expert's post
rakeshd347 wrote:
If x is equal to the sum of the even integers from m to n, inclusive,
where m and n are positive even integers, which of the following
represents the value of x in terms of m and n?

(A) (m+n/2 )(n-m/2 + 1)

(B) 3(m + n)

(c)n^2-m^2/2

(D) 6(m + n)

(E) (m+n/2 )(n-m/2 )

Kudos please if you like my question.

Timing is important here.


Take m=n=2.Thus, x = 2.

A.
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Re: If x is equal to the sum of the even integers [#permalink] New post 22 Apr 2013, 23:17
great thanks.................
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Re: If x is equal to the sum of the even integers from m to n, [#permalink] New post 24 Apr 2013, 12:38
Exactly. Assuming numbers is the easiest way to solve this kind of problem.
Re: If x is equal to the sum of the even integers from m to n,   [#permalink] 24 Apr 2013, 12:38
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If x is equal to the sum of the even integers from m to n,

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