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If x is not equal to -y, is (x-y)/(x+y) > 1? 1) x>0 2) [#permalink]
07 Sep 2007, 07:32

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x is not equal to -y, is (x-y)/(x+y) > 1?
1) x>0
2) y<0> (x+y) ?

SO, multiplying the inequality by (x+y) both sides, the question becomes is (x-y) > (x+y)?

From 1) if x>0, x is +ve
From 2) if y<0, y is -ve

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y). I thought the official answer to be C

but the OE is E, can some one pls explain what is wrong with my analysis.

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y).

If (x-y) is positive and (x+y) is negative the whole expression will be negative, therefore <1>1. Therefore, insufficient. Answer E.

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y).

If (x-y) is positive and (x+y) is negative the whole expression will be negative, therefore <1>1. Therefore, insufficient. Answer E.

I could see that if x-y is positive and x+y negative then less than 1 , and x-y) is positive and x+y positive then greater than 1.

But if you the change the inequality from is (x-y)/(x+y) > 1 to (x-y) > (x+y) and ask yourself is (x-y) > (x+y), you will end up with answer YES.

So probably i should not be altering the inequlaity by multiplying (x+y), which changes the whole picture.

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y).

If (x-y) is positive and (x+y) is negative the whole expression will be negative, therefore <1>1. Therefore, insufficient. Answer E.

I could see that if (x-y) is negative , and (x-y) is positive then (x-y)/(x+y) <1>1, hence E.

But if you the change the inequality from is (x-y)/(x+y) > 1 to (x-y) > (x+y) and ask yourself is (x-y) > (x+y), you will end up with answer YES.

So probably i should not be altering the inequlaity by multiplying (x+y), which changes the whole picture.

In these type of equations we can not change the equality, the way u did.
Cuz (x+y) can be both posotive or negative, if (x+y) is positive then the way u changed the equation is correct, but if it is negative, the sign <> will change to opposite.

I keep getting C,

Plz, can you check if I understand what is given, the HTML sometimes changes the inequality sings, so let me write in words:

X is not equal to minus Y. Is X-Y over X+Y greater than 1?

1) X is more than zero
2) X+Y is more than zero, Y is less than zero, and Y is less than (X+Y)

I see two inequality sings in the 2nd stem, is it right?

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y).

If (x-y) is positive and (x+y) is negative the whole expression will be negative, therefore <1>1. Therefore, insufficient. Answer E.

I could see that if x-y is positive and x+y negative then less than 1 , and x-y) is positive and x+y positive then greater than 1.

But if you the change the inequality from is (x-y)/(x+y) > 1 to (x-y) > (x+y) and ask yourself is (x-y) > (x+y), you will end up with answer YES.

So probably i should not be altering the inequlaity by multiplying (x+y), which changes the whole picture.

While solving inequlaity problems, multipling denominator (bottom part of fraction) to the other part of inequality sign is INCORRECT, it is only possible in equations.

Instead take 1 to left side and simplify the expression.

you will have 2y/(x+y)<0>0 and y>0 will give postive value (to satisfy inequlaity it should be negative since 2y/(x+y)<0)
2) is insufficient because y<0 and x<0 will give positive value (to satisfy inequlaity it should be negative since 2y/(x+y)<0)

both together will not sufficient since we don't know the values, if x is more than two times higher than y than it will give postive value and in other cases negative so Insufficient

Ans: E

Last edited by Ferihere on 07 Sep 2007, 08:39, edited 1 time in total.

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y).

If (x-y) is positive and (x+y) is negative the whole expression will be negative, therefore <1>1. Therefore, insufficient. Answer E.

I could see that if (x-y) is negative , and (x-y) is positive then (x-y)/(x+y) <1>1, hence E.

But if you the change the inequality from is (x-y)/(x+y) > 1 to (x-y) > (x+y) and ask yourself is (x-y) > (x+y), you will end up with answer YES.

So probably i should not be altering the inequlaity by multiplying (x+y), which changes the whole picture.

In these type of equations we can not change the equality, the way u did. Cuz (x+y) can be both posotive or negative, if (x+y) is positive then the way u changed the equation is correct, but if it is negative, the sign <> will change to opposite.

I keep getting C,

Plz, can you check if I understand what is given, the HTML sometimes changes the inequality sings, so let me write in words:

X is not equal to minus Y. Is X-Y over X+Y greater than 1?

1) X is more than zero 2) X+Y is more than zero, Y is less than zero, and Y is less than (X+Y)

I see two inequality sings in the 2nd stem, is it right?

Thanks for the explanation.. Here is the question agian

If X is not equal to minus Y. Is X-Y over X+Y greater than 1?

So From 1 and 2, (x-y) is postive and (x+y) could be positive or negative, but regardless of (x+y) being postive or negative, (x-y) will always be greater than (x+y).

If (x-y) is positive and (x+y) is negative the whole expression will be negative, therefore <1>1. Therefore, insufficient. Answer E.

I could see that if (x-y) is negative , and (x-y) is positive then (x-y)/(x+y) <1>1, hence E.

But if you the change the inequality from is (x-y)/(x+y) > 1 to (x-y) > (x+y) and ask yourself is (x-y) > (x+y), you will end up with answer YES.

So probably i should not be altering the inequlaity by multiplying (x+y), which changes the whole picture.

In these type of equations we can not change the equality, the way u did. Cuz (x+y) can be both posotive or negative, if (x+y) is positive then the way u changed the equation is correct, but if it is negative, the sign <> will change to opposite.

I keep getting C,

Plz, can you check if I understand what is given, the HTML sometimes changes the inequality sings, so let me write in words:

X is not equal to minus Y. Is X-Y over X+Y greater than 1?

1) X is more than zero 2) X+Y is more than zero, Y is less than zero, and Y is less than (X+Y)

I see two inequality sings in the 2nd stem, is it right?

Thanks for the explanation.. Here is the question agian

If X is not equal to minus Y. Is X-Y over X+Y greater than 1?