if x is not equal to -y
is x-y/x+y > 1
Now, we can construct our examples:
1. 2y is always negative (2. y<0)
2. a sign of (x+y) depends on relationship between |x| and |y|. if |x|>|y| then (x+y)>0, otherwise, if |y|<|x| then (x+y)<0
3. x=1, y=-10 and x=10, y=-1
4. Therefore, both conditions are insufficient.
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