pmenon wrote:

if x is not equal to -y

is x-y/x+y > 1

1. x>0

2. y<0

\(\frac{x-y}{x+y}=\frac{x+y-2y}{x+y}=1-\frac{2y}{x+y}>1\)

\(\frac{2y}{x+y}<0\)

Now, we can construct our examples:

1. 2y is always negative (2. y<0)

2. a sign of (x+y) depends on relationship between |x| and |y|. if |x|>|y| then (x+y)>0, otherwise, if |y|<|x| then (x+y)<0

3. x=1, y=-10 and x=10, y=-1

4. Therefore, both conditions are insufficient.

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