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If x is not equal to -y, is (x-y)/(x+y) > 1?

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Senior Manager
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If x is not equal to -y, is (x-y)/(x+y) > 1? [#permalink] New post 03 Apr 2007, 03:16
00:00
A
B
C
D
E

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Q: If x is not equal to -y, is (x-y)/(x+y) > 1?

(1) x > 0
(2) y < 0


I could solve it by picking numbers but it was time-consuming. Could any one please solve it without picking numbers and explain here?

Thanks!

OA: E
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 [#permalink] New post 03 Apr 2007, 03:49
I actually get (C). Can you please explain the OA?
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 [#permalink] New post 03 Apr 2007, 03:56
Sure! :-D

(1) x = 4 and y = -3
(x-y)/(x+y) = 7 which is > 1

But if x = 4 and y = 0
(x-y)/(x+y) = 4 which is = 1 INSUFF

(2) x = 4 and y = -3
(x-y)/(x+y) = 7 which is > 1

But if x = 0 and y = -3
(x-y)/(x+y) = -1 which is < 1 INSUFF

Taking (1) and (2) together:
If x = 4 and y = -3
(x-y)/(x+y) = 7 which is > 1

But if x = 2 and y = -3
(x-y)/(x+y) = -5 which is < 1 INSUFF
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 [#permalink] New post 03 Apr 2007, 04:57
St1.

we have no information about y. if y is larger than x, then (x-y) is going to be negative and (x-y)/(x+y) <1> 1

St2:

same argument above.

St1 and St2:

x > 0 and y <0> 1.
If x = 3, y = -5, then (x-y)/(x+y) < 1.

So still inconclusive.

E
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 [#permalink] New post 03 Apr 2007, 05:00
I don't know why my answer turned out that way in the post. I swear it was correct while i typed but it turned out otherwise.

Anyway, for the last part,

if x = 100, and y = -1/4, then (x-y)/(x+y) will be greater than 1.

if x = 1/4 and y = -100, then (x-y)/(x+y) will be less than 1.

So ans is E.
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 [#permalink] New post 03 Apr 2007, 17:51
:-D ywilfred, I was also facing the same problem...Fig suggested me the solution and it really worked!

When you write your message in the message body, check the button Disable HTML in this post in the Options just below the message body. Then it will be fine :-)
  [#permalink] 03 Apr 2007, 17:51
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