rohitgoel15 wrote:
If x is positive, is x > 3 ?
(1) (x - 1)^2 > 4
(2) (x - 2)^2 > 9
Can someone point a mistake in my method?
(1)
Taking one of the equations:
(x - 1)^2 > 4
x^2 + 1 - 2x > 4
x^2 + 1 - 2x - 4 > 0
x^2 - 3x + 1x - 3 > 0
(x-3) (x+1) > 0
x > 3 and x > -1
while in the explanation given the ans is coming out to be x > 3 and x < -1
Please help ..
If x is positive, is x > 3 ?(1) (x - 1)^2 > 4 -->
(x+1)(x-3)>0 --> roots are -1 and 3. Now, ">" sign indicates that the solution lies to the left of a smaller root and to the right of the larger root:
x<-1 or
x>3. Since given that
x is positive then only one range is valid:
x>3. Sufficient.
(2) (x - 2)^2 > 9 -->
(x+1)(x-5)>0 --> roots are -1 and 5. Again, ">" sign indicates that the solution lies to the left of a smaller root and to the right of the larger root:
x<-1 or
x>5. Since given that
x is positive then only one range is valid:
x>5. Sufficient.
Answer: D.
Solving inequalities:
x2-4x-94661.html#p731476 (
check this one first)
inequalities-trick-91482.htmldata-suff-inequalities-109078.htmlrange-for-variable-x-in-a-given-inequality-109468.html?hilit=extreme#p873535everything-is-less-than-zero-108884.html?hilit=extreme#p868863Hope it helps.
Another approach:If x is positive, is x > 3 ?(1) (x - 1)^2 > 4 --> since both sides of the inequality are non-negative then we can take square root from both parts:
|x-1|>2.
|x-1| is just the distance between 1 and
x on the number line. We are told that this distance is more than 2:
--(-1)----1----3-- so,
x<-1 or
x>3. Since given that
x is positive then only one range is valid:
x>3. Sufficient.
(2) (x - 2)^2 > 9 -->
|x-2|>3. The same here:
|x-2| is just the distance between 2 and
x on the number line. We are told that this distance is more than 3:
--(-1)----2----5-- so,
x<-1 or
x>5. Since given that
x is positive then only one range is valid:
x>5. Sufficient.
Answer: D.
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