If x is positive, is x >3? 1. (x-1)^2 > 4 2. (x-2)^2 : Quant Question Archive [LOCKED]
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# If x is positive, is x >3? 1. (x-1)^2 > 4 2. (x-2)^2

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Senior Manager
Joined: 05 Oct 2008
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If x is positive, is x >3? 1. (x-1)^2 > 4 2. (x-2)^2 [#permalink]

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24 Dec 2008, 03:12
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x is positive, is x >3?

1. (x-1)^2 > 4
2. (x-2)^2 >9
Manager
Joined: 11 Apr 2008
Posts: 202
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Kudos [?]: 17 [0], given: 1

Re: Exponents [#permalink]

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24 Dec 2008, 07:30
I think the ans is D

x can be either >3 or <-3 but if the x is positive then it will satisfy the condition in statement 1
similarly x can be either >5 or <-1 but if x is positive then it will satisfy the condition in the statement 2.

What is the OA and its explanation?
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Senior Manager
Joined: 05 Oct 2008
Posts: 274
Followers: 3

Kudos [?]: 379 [0], given: 22

Re: Exponents [#permalink]

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24 Dec 2008, 07:47
would you please post your solution...how you derive +3/-3
Senior Manager
Joined: 05 Oct 2008
Posts: 274
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Kudos [?]: 379 [0], given: 22

Re: Exponents [#permalink]

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24 Dec 2008, 07:52
How does one solve for such problems?

I get x^2 - 2x - 3 >0
which gives
x>-1
x>3
as the solution

statement 2 i get

x^2 - 4x - 5 >0
which gives
x>-1
x>5
Manager
Joined: 11 Apr 2008
Posts: 202
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Kudos [?]: 17 [0], given: 1

Re: Exponents [#permalink]

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24 Dec 2008, 08:14
study you are right
My bad,
for statement 1, the values x>3 and x<-1 satisfies the condition
similarly for statement 2, the values x>5 and x<-1 satisfies the condition.
But as it is mentioned x is positive we see in both satements the value of x comes out more than 3.
So each statement is sufficient. D
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Re: Exponents   [#permalink] 24 Dec 2008, 08:14
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# If x is positive, is x >3? 1. (x-1)^2 > 4 2. (x-2)^2

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