Find all School-related info fast with the new School-Specific MBA Forum

It is currently 01 Aug 2015, 15:02
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If x is positive, which of the following could be correct

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Retired Moderator
User avatar
Status: 2000 posts! I don't know whether I should feel great or sad about it! LOL
Joined: 04 Oct 2009
Posts: 1720
Location: Peru
Schools: Harvard, Stanford, Wharton, MIT & HKS (Government)
WE 1: Economic research
WE 2: Banking
WE 3: Government: Foreign Trade and SMEs
Followers: 79

Kudos [?]: 484 [0], given: 109

Re: If x is positive, which of the following could be correct [#permalink] New post 27 Jun 2012, 13:11
Bunuel, please check my reasoning about statement III:

Statement III says \(2x < x^2 < \frac{1}{x}\)

So, we analyze part by part of this compound inequality:

a) \(2x < x^2\)
then, \(x>2\)

b) \(x^2 < \frac{1}{x}\)

then,\(x^3<1\) ==> \(x < 1\)

So, we have \(x>2\) and \(x<1\).
That's impossible! if \(x>2\), x cannot be less than 1 at the same time.
Statement III could not be correct!

Please, confirm.
_________________

"Life’s battle doesn’t always go to stronger or faster men; but sooner or later the man who wins is the one who thinks he can."

My Integrated Reasoning Logbook / Diary: my-ir-logbook-diary-133264.html

GMAT Club Premium Membership - big benefits and savings

Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 28781
Followers: 4594

Kudos [?]: 47463 [0], given: 7123

Re: If x is positive, which of the following could be correct [#permalink] New post 28 Jun 2012, 01:15
Expert's post
metallicafan wrote:
Bunuel, please check my reasoning about statement III:

Statement III says \(2x < x^2 < \frac{1}{x}\)

So, we analyze part by part of this compound inequality:

a) \(2x < x^2\)
then, \(x>2\)

b) \(x^2 < \frac{1}{x}\)

then,\(x^3<1\) ==> \(x < 1\)

So, we have \(x>2\) and \(x<1\).
That's impossible! if \(x>2\), x cannot be less than 1 at the same time.
Statement III could not be correct!

Please, confirm.


Yes, your reasoning for option III is correct.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

GMAT Club Premium Membership - big benefits and savings

Intern
Intern
avatar
Joined: 18 Jun 2012
Posts: 44
Followers: 1

Kudos [?]: 4 [0], given: 15

Re: If x is positive, which of the following could be correct [#permalink] New post 28 Jul 2012, 19:24
The question asked "what could be the correct ordering" means it asked for the possibilities.
What is question asked "what must be the correct ordering" ? In that case would we be required to choose an option which is true for all scenarios ?
4 KUDOS received
Director
Director
User avatar
Joined: 22 Mar 2011
Posts: 612
WE: Science (Education)
Followers: 78

Kudos [?]: 625 [4] , given: 43

Re: If x is positive, which of the following could be correct [#permalink] New post 29 Jul 2012, 00:37
4
This post received
KUDOS
Please, refer to the attached drawing, in which the three graphs \(y=1/x,\) \(y=2x,\) and \(y=x^2\) are depicted for \(x>0\).
The exact values for A, B, and C can be worked out, but they are not important to establish the order of the three algebraic expressions.

So, the correct orderings are:
If \(x\) between 0 and A: \(x^2<2x<1/x\)
If \(x\) between A and B: \(x^2<1/x<2x\)
If \(x\) between B and C: \(1/x<x^2<2x\)
If \(x\) greater than C: \(1/x<2x<x^2\)

We can see that only the first two of the above options are listed as answers (I and II).

Answer: D.
Attachments

3Graphs.jpg
3Graphs.jpg [ 15.15 KiB | Viewed 4084 times ]


_________________

PhD in Applied Mathematics
Love GMAT Quant questions and running.

Expert Post
1 KUDOS received
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 5746
Location: Pune, India
Followers: 1446

Kudos [?]: 7598 [1] , given: 186

Re: If x is positive, which of the following could be correct [#permalink] New post 29 Jul 2012, 21:58
1
This post received
KUDOS
Expert's post
smartmanav wrote:
The question asked "what could be the correct ordering" means it asked for the possibilities.
What is question asked "what must be the correct ordering" ? In that case would we be required to choose an option which is true for all scenarios ?


The ordering will be different for different values of x so the question cannot ask for a single correct ordering.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199

Veritas Prep Reviews

Current Student
User avatar
Joined: 23 Oct 2010
Posts: 386
Location: Azerbaijan
Concentration: Finance
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
Followers: 15

Kudos [?]: 198 [0], given: 73

GMAT ToolKit User
Re: If x is positive, which of the following could be correct [#permalink] New post 07 Aug 2012, 23:50
given that x>0
1 ) x^2 < 2X<1/X lets just check x^2 < 2X => 0 <x<2 ; 2X<1/X => 0<x<1/\sqrt{2}
these 2 inequities do not conradict each other. so, 1) is ok

2) x^2 <1/X< 2X check them - x^2 <1/X => 0<x<1 ; 1/X< 2X => x> 1/\sqrt{2}
these 2 inequities do not conradict each other. so, 2) is ok

3) 2X< x^2 <1/X check them - 2X< x^2 => x>2 ; x^2 <1/X => x<1
these 2 inequities conradict each other. so, 3) is not ok


p.s. dont know why such symbols as sqroot , fraction ets dont work. :oops:
_________________

Happy are those who dream dreams and are ready to pay the price to make them come true

Expert Post
Moderator
Moderator
User avatar
Joined: 01 Sep 2010
Posts: 2640
Followers: 487

Kudos [?]: 3773 [0], given: 727

Re: If x is positive, which of the following could be correct [#permalink] New post 13 Dec 2012, 06:28
Expert's post
picking numbers, both integers and not and only positive.

In all cases only the 3 case doesn't work, so pretty fast you can reach D

in this question youhave to be really comfortable with theory to solve it, otherwise is best and safe picking number .
_________________

COLLECTION OF QUESTIONS
Quant: 1. Bunuel Signature Collection - The Next Generation 2. Bunuel Signature Collection ALL-IN-ONE WITH SOLUTIONS 3. Veritas Prep Blog PDF Version
Verbal:1. Best EXTERNAL resources to tackle the GMAT Verbal Section 2. e-GMAT's ALL CR topics-Consolidated 3. New Critical Reasoning question bank by carcass 4. Meaning/Clarity SC Question Bank by Carcass_Souvik 5. e-GMAT's ALL SC topics-Consolidated-2nd Edition 6. The best reading to improve Reading Comprehension 7.Verbal question bank and Directories

Intern
Intern
avatar
Joined: 13 Dec 2012
Posts: 4
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: If x is positive, which of the following could be correct [#permalink] New post 13 Dec 2012, 22:41
if x = 1/2, then 1/1/2 = 2 which is greater than 2(1/2)
Director
Director
avatar
Joined: 08 Jun 2010
Posts: 680
Followers: 0

Kudos [?]: 47 [0], given: 152

Re: If x is positive, which of the following could be correct [#permalink] New post 13 Dec 2012, 23:30
positiveness or negativeness is important to inequalit

because x is positive we can multiple both sides of inequality with x and keep the same mark.for example

x^2<2x<1/x

is the same as

x^3<2x^2<1

(if x is negative we have to change the mark of the inequality. this question is not relevant to that cases)

now solve 2 inequality independently . this can be done quick.

this questions can be done in less than 3 minutes. Other method takes longer time and in fact is not good.

pls, comment.
Intern
Intern
avatar
Joined: 28 Aug 2012
Posts: 21
Location: United States
Concentration: General Management, Leadership
Schools: Thunderbird '16
GPA: 3.37
WE: Information Technology (Consulting)
Followers: 1

Kudos [?]: 32 [0], given: 6

GMAT ToolKit User
Re: If x is positive, which of the following could be correct [#permalink] New post 11 May 2013, 01:05
Hey Karishma,

I feel below highlighted part is not correct. Please check. If I am wrong, please explain. thanks.

VeritasPrepKarishma wrote:
Vavali wrote:
If x is positive, which of the following could be correct ordering of \(\frac{1}{x}\), \(2x\), and \(x^2\)?

(I) \(x^2 < 2x < \frac{1}{x}\)
(II) \(x^2 < \frac{1}{x} < 2x\)
(III) \(2x < x^2 < \frac{1}{x}\)

(a) none
(b) I only
(c) III only
(d) I and II
(e) I, II and III


Let's look at this question logically. There will be some key takeaways here so don't focus on the question and the (long) solution. Focus on the logic.

First of all, we are just dealing with positives so life is simpler.
To compare two terms e.g. \(x^2\) and \(2x\), we should focus on the points where they are equal. \(x^2 = 2x\) holds when \(x = 2\).
When \(x < 2, x^2 < 2x\)
When \(x > 2, x^2 > 2x\)

Similarly \(1/x = x^2\) when \(x = 1\)
When \(x < 1, 1/x > x^2\).
When \(x > 1, 1/x > x^2\) Are you sure this is correct? I think.. we can use x=4 here, then 1/4>16 .. which is not correct.

Going on, \(1/x = 2x\) when \(x = 1/\sqrt{2}\)
When \(x < 1/\sqrt{2}, 1/x > 2x\)
When \(x > 1/\sqrt{2}, 1/x < 2x\)

So now you know that:
If \(x < 1/\sqrt{2}\),
\(1/x > 2x, 1/x > x^2\) and \(x^2 < 2x\)
So \(x^2 < 2x < 1/x\) is possible.

If \(1/\sqrt{2} < x < 1\)
\(1/x < 2x, 1/x > x^2\)
So \(x^2 < 1/x < 2x\) is possible.

If \(x > 1\)
\(1/x < 2x, 1/x > x^2\)
So \(x^2 < 1/x < 2x\) is possible. (Same as above)

For no positive values of x is the third relation possible.
Expert Post
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 5746
Location: Pune, India
Followers: 1446

Kudos [?]: 7598 [0], given: 186

Re: If x is positive, which of the following could be correct [#permalink] New post 11 May 2013, 02:12
Expert's post
yogirb8801 wrote:
Hey Karishma,

I feel below highlighted part is not correct. Please check. If I am wrong, please explain. thanks.

VeritasPrepKarishma wrote:
Vavali wrote:
If x is positive, which of the following could be correct ordering of \(\frac{1}{x}\), \(2x\), and \(x^2\)?

(I) \(x^2 < 2x < \frac{1}{x}\)
(II) \(x^2 < \frac{1}{x} < 2x\)
(III) \(2x < x^2 < \frac{1}{x}\)

(a) none
(b) I only
(c) III only
(d) I and II
(e) I, II and III


Let's look at this question logically. There will be some key takeaways here so don't focus on the question and the (long) solution. Focus on the logic.

First of all, we are just dealing with positives so life is simpler.
To compare two terms e.g. \(x^2\) and \(2x\), we should focus on the points where they are equal. \(x^2 = 2x\) holds when \(x = 2\).
When \(x < 2, x^2 < 2x\)
When \(x > 2, x^2 > 2x\)

Similarly \(1/x = x^2\) when \(x = 1\)
When \(x < 1, 1/x > x^2\).
When \(x > 1, 1/x > x^2\) Are you sure this is correct? I think.. we can use x=4 here, then 1/4>16 .. which is not correct.

Going on, \(1/x = 2x\) when \(x = 1/\sqrt{2}\)
When \(x < 1/\sqrt{2}, 1/x > 2x\)
When \(x > 1/\sqrt{2}, 1/x < 2x\)

So now you know that:
If \(x < 1/\sqrt{2}\),
\(1/x > 2x, 1/x > x^2\) and \(x^2 < 2x\)
So \(x^2 < 2x < 1/x\) is possible.

If \(1/\sqrt{2} < x < 1\)
\(1/x < 2x, 1/x > x^2\)
So \(x^2 < 1/x < 2x\) is possible.

If \(x > 1\)
\(1/x < 2x, 1/x > x^2\)
So \(x^2 < 1/x < 2x\) is possible. (Same as above)

For no positive values of x is the third relation possible.


That is a typo. If you notice, for every case, the relation is opposite on the opposite sides of the equality value. So the relation that holds in x < 1 will be opposite to the relation that holds when x > 1.
That did mess up the entire explanation. Good you pointed it out. I have edited the original post.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199

Veritas Prep Reviews

Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 28781
Followers: 4594

Kudos [?]: 47463 [0], given: 7123

Re: If x is positive, which of the following could be correct [#permalink] New post 05 Jul 2013, 01:26
Expert's post
Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE


_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

GMAT Club Premium Membership - big benefits and savings

Intern
Intern
avatar
Joined: 15 Jul 2013
Posts: 1
Followers: 0

Kudos [?]: 1 [0], given: 3

Re: If X is positive [#permalink] New post 15 Sep 2013, 09:47
1
This post was
BOOKMARKED
lylya4 wrote:
Vavali wrote:
If x is positive, which of the following could be correct ordering of 1/x, 2x, and x^2?

(I) X^2 < 2x < 1/x
(II) x^2 < 1/x < 2x
(III) 2x < x^2 < 1/x

(a) none
(b) I only
(c) III only
(d) I and II
(e) I, II and III


could be correct ordering

So if we can find any example that satisfy the inequation, that statement will be correct

(I) x = 0.1 => 0.01 < 0.2 < 10
(II) x= 1/2 => 1/4 < 1/2 < 1

(III)
2x < x^2 <=> x ( 2 -x) < 0, x > 0 then x > 2

with x > 2 ==> x^2 < 1/x <=> x^3 < 1 <=> x < 1

So (III) can't happen

The answer is D


if x = 1/2, 1/x = 2 .. wrong example used
Senior Manager
Senior Manager
avatar
Joined: 07 Sep 2010
Posts: 338
Followers: 4

Kudos [?]: 273 [0], given: 136

Re: If x is positive, which of the following could be correct [#permalink] New post 02 Oct 2013, 08:40
Hello Bunuel,
Can you show us graphical approach to this question.
I was able to draw the graph for all three equations and intersection points, however, I was not able to negate the third ordering. Would you please help me out.

Thanks
imhimanshu
P.S - How can I post graphs here.
_________________

+1 Kudos me, Help me unlocking GMAT Club Tests

Expert Post
1 KUDOS received
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 5746
Location: Pune, India
Followers: 1446

Kudos [?]: 7598 [1] , given: 186

Re: If x is positive, which of the following could be correct [#permalink] New post 02 Oct 2013, 20:21
1
This post received
KUDOS
Expert's post
imhimanshu wrote:
Hello Bunuel,
Can you show us graphical approach to this question.
I was able to draw the graph for all three equations and intersection points, however, I was not able to negate the third ordering. Would you please help me out.

Thanks
imhimanshu
P.S - How can I post graphs here.


Here is the graph:
Attachment:
Ques3.jpg
Ques3.jpg [ 11.4 KiB | Viewed 2244 times ]


III. 2x < x^2 < 1/x

For 2x to be less than x^2, the graph of 2x should lie below the graph of x^2. This happens when the graph of 2x is the red line.
For x^2 to be less than 1/x at the same time, the graph of x^2 should lie below the graph of 1/x in the region of the red line. But in the region of the red line, the graph of x^2 is never below the graph of 1/x. It will never be because graph of 1/x is going down toward y = 0 while graph of x^2 is going up toward y = infinity.
Hence this inequality will not hold for any region.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199

Veritas Prep Reviews

SVP
SVP
User avatar
Joined: 06 Sep 2013
Posts: 2046
Concentration: Finance
GMAT 1: 770 Q0 V
Followers: 30

Kudos [?]: 323 [0], given: 355

GMAT ToolKit User
Re: If x is positive, which of the following could be correct [#permalink] New post 14 Feb 2014, 07:49
Bunuel wrote:
imhimanshu wrote:
Hi Bunnel,

Could you please provide a reasoning to the below text... how did you find the range...Pls help


The reasoning is that in these ranges x (2x), 1/x and x^2 are ordered differently:

For \(x>2\) --> \(x^2\) has the largest value. Since no option offers this we know that \(x\) cannot be more that 2;
For \(1<x<2\) --> \(2x\) has the largest value, then comes \(x^2\). Since no option offers this we know that \(x\) cannot be from this range either;

So, we are left with last range: \(0<x<1\). In this case \(x^2\) has the least value. Options, I and II offer this, so we should concentrate on them and test the values of x from 0 to 1.

Hope it's clear.


Hi Bunuel.

How do you know which numbers to pick? I mean for example 0.9 for the second statement. Any clues?

Thanks
Cheers
J
Intern
Intern
avatar
Joined: 09 Dec 2013
Posts: 31
Followers: 1

Kudos [?]: 36 [0], given: 8

Re: If x is positive, which of the following could be correct [#permalink] New post 22 Feb 2014, 07:48
I picked numbers: 1/2, 1, 3/2, 2, 3

However, it didn occur to me that I must look something like 0.9. Request experts to help me understand the logic behind picking such numbers. Have my actual GMAT in 10 days, any help would be immensely valuable!

Thanks!
Expert Post
1 KUDOS received
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 5746
Location: Pune, India
Followers: 1446

Kudos [?]: 7598 [1] , given: 186

Re: If x is positive, which of the following could be correct [#permalink] New post 24 Feb 2014, 01:12
1
This post received
KUDOS
Expert's post
abdb wrote:
I picked numbers: 1/2, 1, 3/2, 2, 3

However, it didn occur to me that I must look something like 0.9. Request experts to help me understand the logic behind picking such numbers. Have my actual GMAT in 10 days, any help would be immensely valuable!

Thanks!


I have answered your query using this very question here: http://www.veritasprep.com/blog/2013/05 ... on-points/
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199

Veritas Prep Reviews

Senior Manager
Senior Manager
User avatar
Joined: 10 Mar 2013
Posts: 250
Followers: 1

Kudos [?]: 34 [0], given: 2146

Re: If x is positive, which of the following could be correct [#permalink] New post 30 Jul 2014, 19:40
What a horrific problem?! I think a fast and simple way is to graph all functions and compare all vertically. Doing this, it can be easy to see that III is impossible.
Manager
Manager
avatar
Joined: 17 Apr 2013
Posts: 66
Location: United States
Concentration: Other, Finance
Schools: SDSU '16
GMAT 1: 660 Q47 V34
GPA: 2.76
WE: Analyst (Real Estate)
Followers: 0

Kudos [?]: 34 [0], given: 298

GMAT ToolKit User
Re: If x is positive, which of the following could be correct [#permalink] New post 13 Aug 2014, 10:39
lylya4 wrote:
Vavali wrote:
If x is positive, which of the following could be correct ordering of 1/x, 2x, and x^2?

(I) X^2 < 2x < 1/x
(II) x^2 < 1/x < 2x
(III) 2x < x^2 < 1/x

(a) none
(b) I only
(c) III only
(d) I and II
(e) I, II and III


could be correct ordering

So if we can find any example that satisfy the inequation, that statement will be correct

(I) x = 0.1 => 0.01 < 0.2 < 10
(II) x= 1/2 => 1/4 < 1/2 < 1

(III)
2x < x^2 <=> x ( 2 -x) < 0, x > 0 then x > 2

with x > 2 ==> x^2 < 1/x <=> x^3 < 1 <=> x < 1

So (III) can't happen

The answer is D


double check your calculation for x= 1/2 the equation won't hold true
1/0.5 = 2
_________________

Please +1 KUDO if my post helps. Thank you.

Re: If x is positive, which of the following could be correct   [#permalink] 13 Aug 2014, 10:39

Go to page   Previous    1   2   3    Next  [ 42 posts ] 

    Similar topics Author Replies Last post
Similar
Topics:
4 Experts publish their posts in the topic If x > 0, which of the following could be true? Bunuel 5 03 Dec 2014, 07:18
3 Experts publish their posts in the topic If (x - 3)^2 = 225, which of the following could be the carcass 7 24 Feb 2013, 15:57
12 Experts publish their posts in the topic If x is positive, which of the following could be the butterfly 12 01 Nov 2010, 16:28
If = 3, which of the following could be the value of x – 4? kairoshan 8 18 Nov 2009, 20:38
Experts publish their posts in the topic If x is positive which of the following could be the correct Sam Kana 14 03 Nov 2006, 16:44
Display posts from previous: Sort by

If x is positive, which of the following could be correct

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.