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If x is positive, which of the following could be correct

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Manager
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If x is positive, which of the following could be correct [#permalink] New post 02 Jan 2009, 02:19
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If x is positive, which of the following could be correct ordering of 1/x, 2x, x^2

I. x^2 < 2x < 1/x

II. x^2 < 1/x <2x

III. 2x < x^2 < 1/x


1) None
2) I only
3) III only
4) I and III only
4) I , II and III
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Re: correct ordering of expressions [#permalink] New post 02 Jan 2009, 16:10
krishan wrote:
If x is positive, which of the following could be correct ordering of 1/x, 2x, x^2

I. x^2 < 2x < 1/x
II. x^2 < 1/x <2x
III. 2x < x^2 < 1/x


1) None
2) I only
3) III only
4) I and III only
4) I , II and III



One of the quite often discussed questions: 7-p441788?t=61028&hilit=ordering#p441788
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Re: correct ordering of expressions [#permalink] New post 23 Jan 2009, 02:46
krishan, can you revise the answer choices for typo?
I get I and II, but there is no such choice.
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Re: correct ordering of expressions [#permalink] New post 23 Jan 2009, 07:40
krishan wrote:
If x is positive, which of the following could be correct ordering of 1/x, 2x, x^2

I. x^2 < 2x < 1/x

II. x^2 < 1/x <2x

III. 2x < x^2 < 1/x


1) None
2) I only
3) III only
4) I and III only
4) I , II and III


I too got I and II only.
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Re: correct ordering of expressions [#permalink] New post 23 Jan 2009, 09:05
acc to GMATTIGER'S link the 4th option is I and II, so there is deifinitely typo error. Now can u pls explain ur choice?In such cases how shld one chose nos?

botirvoy wrote:
krishan, can you revise the answer choices for typo?
I get I and II, but there is no such choice.
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Re: correct ordering of expressions [#permalink] New post 23 Jan 2009, 09:19
ritula wrote:
acc to GMATTIGER'S link the 4th option is I and II, so there is deifinitely typo error. Now can u pls explain ur choice?In such cases how shld one chose nos?

botirvoy wrote:
krishan, can you revise the answer choices for typo?
I get I and II, but there is no such choice.


to make it easy.. multiple with x throug all options
I x^2 < 2x < 1/x
--> x^3<2x^2 <1
substitiute x=1/2 1/8<1/2<1
could be the answer choice.
II. x^2 < 1/x <2x

--> x^3 <1 <2x^2
here assume value such that 2x^2>1 ..
X= 1/sqrt(2) 2x^2=1
above equation could be answer when x<1 and x>1/sqrt(2)


III. 2x < x^2 < 1/x

-->2x^2 <x^3 <1
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Manager
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Joined: 28 Jul 2004
Posts: 136
Location: Melbourne
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Re: correct ordering of expressions [#permalink] New post 23 Jan 2009, 15:04
Thanks guys for your help. Apologies for the typo.
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kris

Re: correct ordering of expressions   [#permalink] 23 Jan 2009, 15:04
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