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If x/(x+y) = 6 then y/(y+x)

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If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 08 Feb 2013, 14:32
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Question Stats:

77% (02:20) correct 23% (01:31) wrong based on 113 sessions

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If \(\frac{x}{x+y}\)=6 then \(\frac{y}{y+x}\) =

A -5
B 5/11
C 1
D 11/5
E 5
[Reveal] Spoiler: OA
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 08 Feb 2013, 21:54
x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 09 Feb 2013, 13:03
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 09 Feb 2013, 22:25
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KUDOS
Here is another method:
x/(x+y) = 6
=> x/(x+y) - 1 = 6 - 1
=> (x -x -y)/(x+y) = 5
=> -y/(x+y) = 5
or y/(x+y) -5

Option A
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 16 Feb 2013, 14:48
carcass wrote:
GyanOne wrote:
x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A



I do not understand this passage



x/(x+y) = 6 //this statement is already given in the question
=> (x+y-y)/(x+y) = 6 // this statement adds and subtracts y from the numerator so that we get the form y/(x+y) on one side
=> 1 - y/(x+y) = 6 // this step groups ((x+y)/(x+y) -y/(x+y))
=> y/(x+y) = -5
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 19 Feb 2013, 01:53
Method I:

\(\frac{x}{x+y} = 6\)

Reciprocal both sides

\(\frac{x+y}{x} = \frac{1}{6}\)

\(1 + \frac{y}{x} = \frac{1}{6}\)

\(\frac{y}{x} = \frac{-5}{6}\)

Apply componendo / dividendo

\(\frac{y}{x+y} = \frac{-5}{6-5}\)

\(\frac{y}{x+y} = -5\)

Method II

\(\frac{x}{x+y} = 6\)

\(x+y = \frac{x}{6}\).............. (1)

\(y = \frac{x}{6} - x\)

\(y = \frac{-5x}{6}\) ............ (2)

Dividing (2) by (1)

\(\frac{y}{x+y} = \frac{-5x}{6} * \frac{6}{x}\)

\(\frac{y}{x+y} = -5\)
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

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New post 08 Jul 2014, 03:21
x/(x+y) = 6
=(x+y-y)/(x+y) = 6
=1 - y/(x+y) = 6
=y/(x+y) = -5 Ans
Option A (-5) is correct..
Re: If x/(x+y) = 6 then y/(y+x)   [#permalink] 08 Jul 2014, 03:21
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