If x/(x+y) = 6 then y/(y+x)

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If x/(x+y) = 6 then y/(y+x) [#permalink]

08 Feb 2013, 14:32

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Question Stats:

76% (02:14) correct

24% (01:17) wrong

based on 3 sessions

If \frac{x}{x+y}=6 then \frac{y}{y+x} =

A -5
B 5/11
C 1
D 11/5
E 5

[Reveal] Spoiler: OA

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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

08 Feb 2013, 21:54

x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

09 Feb 2013, 13:03

GyanOne wrote:

x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A

I do not understand this passage
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

09 Feb 2013, 22:25

Here is another method:
x/(x+y) = 6
=> x/(x+y) - 1 = 6 - 1
=> (x -x -y)/(x+y) = 5
=> -y/(x+y) = 5
or y/(x+y) -5

Option A
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

16 Feb 2013, 14:48

carcass wrote:

GyanOne wrote:

x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A

I do not understand this passage

x/(x+y) = 6 //this statement is already given in the question
=> (x+y-y)/(x+y) = 6 // this statement adds and subtracts y from the numerator so that we get the form y/(x+y) on one side
=> 1 - y/(x+y) = 6 // this step groups ((x+y)/(x+y) -y/(x+y))
=> y/(x+y) = -5
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink]

19 Feb 2013, 01:53

One more method here:

x
------ = 6; so (x + y) / x = 1/6
x + y

Now, 1 + y 1
---- = ------\frac{[fraction][}{fraction]}
x 6
So, y/x = -5/6

So , x/y = -6/5 ------------ (1)

Adding 1 on both sides of (1)

(y + x) / y = -1/5

Reciprocal both sides.......

y / (x + y) = -5

Re: If x/(x+y) = 6 then y/(y+x) [#permalink] 19 Feb 2013, 01:53

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If x/(x+y) = 6 then y/(y+x)

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If x/(x+y) = 6 then y/(y+x)

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