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If x/(x+y) = 6 then y/(y+x)

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If x/(x+y) = 6 then y/(y+x) [#permalink] New post 08 Feb 2013, 13:32
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Question Stats:

73% (02:35) correct 27% (01:51) wrong based on 60 sessions
If \frac{x}{x+y}=6 then \frac{y}{y+x} =

A -5
B 5/11
C 1
D 11/5
E 5
[Reveal] Spoiler: OA
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink] New post 08 Feb 2013, 20:54
x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A

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Re: If x/(x+y) = 6 then y/(y+x) [#permalink] New post 09 Feb 2013, 12:03
Expert's post
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Re: If x/(x+y) = 6 then y/(y+x) [#permalink] New post 09 Feb 2013, 21:25
Here is another method:
x/(x+y) = 6
=> x/(x+y) - 1 = 6 - 1
=> (x -x -y)/(x+y) = 5
=> -y/(x+y) = 5
or y/(x+y) -5

Option A

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Re: If x/(x+y) = 6 then y/(y+x) [#permalink] New post 16 Feb 2013, 13:48
carcass wrote:
GyanOne wrote:
x/(x+y) = 6
=> (x+y-y)/(x+y) = 6
=> 1 - y/(x+y) = 6
=> y/(x+y) = -5

Option A



I do not understand this passage



x/(x+y) = 6 //this statement is already given in the question
=> (x+y-y)/(x+y) = 6 // this statement adds and subtracts y from the numerator so that we get the form y/(x+y) on one side
=> 1 - y/(x+y) = 6 // this step groups ((x+y)/(x+y) -y/(x+y))
=> y/(x+y) = -5

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Re: If x/(x+y) = 6 then y/(y+x) [#permalink] New post 19 Feb 2013, 00:53
Method I:

\frac{x}{x+y} = 6

Reciprocal both sides

\frac{x+y}{x} = \frac{1}{6}

1 + \frac{y}{x} = \frac{1}{6}

\frac{y}{x} = \frac{-5}{6}

Apply componendo / dividendo

\frac{y}{x+y} = \frac{-5}{6-5}

\frac{y}{x+y} = -5

Method II

\frac{x}{x+y} = 6

x+y = \frac{x}{6}.............. (1)

y = \frac{x}{6} - x

y = \frac{-5x}{6} ............ (2)

Dividing (2) by (1)

\frac{y}{x+y} = \frac{-5x}{6} * \frac{6}{x}

\frac{y}{x+y} = -5

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Re: If x/(x+y) = 6 then y/(y+x) [#permalink] New post 08 Jul 2014, 02:21
x/(x+y) = 6
=(x+y-y)/(x+y) = 6
=1 - y/(x+y) = 6
=y/(x+y) = -5 Ans
Option A (-5) is correct..
Re: If x/(x+y) = 6 then y/(y+x)   [#permalink] 08 Jul 2014, 02:21
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