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If x + y >0, is x > |y|? (1) x > y (2) y < 0

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Director
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If x + y >0, is x > |y|? (1) x > y (2) y < 0 [#permalink] New post 13 Dec 2003, 20:43
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A
B
C
D
E

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(N/A)

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If x + y >0, is x > |y|?

(1) x > y
(2) y < 0
CEO
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Re: G+ DS-7-22 [#permalink] New post 13 Dec 2003, 21:45
kpadma wrote:
If x + y >0, is x > |y|?

(1) x > y
(2) y < 0


From stem, We know x> -y

Simply, does x satisfy x >y?


1... is sufficient.

2... not sufficient

A
Director
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 [#permalink] New post 13 Dec 2003, 22:31
we got X>-Y
A tells, X>Y

cool, we know it 's A
Director
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 [#permalink] New post 13 Dec 2003, 22:35
I got A.

1) suffish

2) insuffish
Director
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 [#permalink] New post 14 Dec 2003, 04:13
If y<0 then from x+y>0 follows that x>-(-Y) or x>y, and x>-y, or x>IyI if y=-5, x=6..IMO should be D..
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 [#permalink] New post 16 Dec 2003, 12:57
Official answer is D

Anyone want to explain why (2) is sufficient ?
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 [#permalink] New post 16 Dec 2003, 13:06
If Y is negative, and added to X to get a positive result, then x must be "bigger" than Y is "small"
Director
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 [#permalink] New post 16 Dec 2003, 13:09
Hey, BG, If you'd like, you can use shift-\, or | to denote absolute value.

It's the key just below backspcae...
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 [#permalink] New post 16 Dec 2003, 13:38
I completely overlooked (2)

Question Stem

X+Y>0 Therefore, X>-Y. Thus, it is unclear if Y is a positive number or a negative number. If Y is a positive number, Then X could be positive or negative. However, if Y is negative then X MUST be positive - given the assumption X>-Y. Number 2 tells us that Y is a negative number. Thus X>-(-Y) = X>|Y|. This is a "Yes/No" question - number 2 allows to answer a definitive "Yes"!
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 [#permalink] New post 17 Dec 2003, 05:50
kpadma wrote:
Official answer is D

Anyone want to explain why (2) is sufficient ?

Statement 2 tells us that y is negative. The statement in the original problem tells us x + y > 0. So if y is negative, according to Stmnt2, then for [x + y > 0] be true x has to be a little more than absolute value of y. And that answers question.
  [#permalink] 17 Dec 2003, 05:50
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