Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 27 Mar 2015, 17:57

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x + y >0, is x > |y|? (1) x > y (2) y < 0

Author Message
TAGS:
Director
Joined: 03 Jul 2003
Posts: 656
Followers: 2

Kudos [?]: 21 [0], given: 0

If x + y >0, is x > |y|? (1) x > y (2) y < 0 [#permalink]  13 Dec 2003, 20:43
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If x + y >0, is x > |y|?

(1) x > y
(2) y < 0
CEO
Joined: 15 Aug 2003
Posts: 3470
Followers: 61

Kudos [?]: 697 [0], given: 781

Re: G+ DS-7-22 [#permalink]  13 Dec 2003, 21:45
If x + y >0, is x > |y|?

(1) x > y
(2) y < 0

From stem, We know x> -y

Simply, does x satisfy x >y?

1... is sufficient.

2... not sufficient

A
Director
Joined: 13 Nov 2003
Posts: 971
Location: Florida
Followers: 1

Kudos [?]: 31 [0], given: 0

we got X>-Y
A tells, X>Y

cool, we know it 's A
Director
Joined: 14 Oct 2003
Posts: 589
Location: On Vacation at My Crawford, Texas Ranch
Followers: 1

Kudos [?]: 8 [0], given: 0

I got A.

1) suffish

2) insuffish
Director
Joined: 13 Nov 2003
Posts: 794
Location: BULGARIA
Followers: 1

Kudos [?]: 25 [0], given: 0

If y<0 then from x+y>0 follows that x>-(-Y) or x>y, and x>-y, or x>IyI if y=-5, x=6..IMO should be D..
Director
Joined: 03 Jul 2003
Posts: 656
Followers: 2

Kudos [?]: 21 [0], given: 0

Anyone want to explain why (2) is sufficient ?
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 8 [0], given: 0

If Y is negative, and added to X to get a positive result, then x must be "bigger" than Y is "small"
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 8 [0], given: 0

Hey, BG, If you'd like, you can use shift-\, or | to denote absolute value.

It's the key just below backspcae...
Director
Joined: 14 Oct 2003
Posts: 589
Location: On Vacation at My Crawford, Texas Ranch
Followers: 1

Kudos [?]: 8 [0], given: 0

I completely overlooked (2)

Question Stem

X+Y>0 Therefore, X>-Y. Thus, it is unclear if Y is a positive number or a negative number. If Y is a positive number, Then X could be positive or negative. However, if Y is negative then X MUST be positive - given the assumption X>-Y. Number 2 tells us that Y is a negative number. Thus X>-(-Y) = X>|Y|. This is a "Yes/No" question - number 2 allows to answer a definitive "Yes"!
Manager
Joined: 26 Aug 2003
Posts: 233
Location: United States
Followers: 1

Kudos [?]: 2 [0], given: 0

Anyone want to explain why (2) is sufficient ?

Statement 2 tells us that y is negative. The statement in the original problem tells us x + y > 0. So if y is negative, according to Stmnt2, then for [x + y > 0] be true x has to be a little more than absolute value of y. And that answers question.
Similar topics Replies Last post
Similar
Topics:
If x # -y , is (x-y)/(x+y) > 1 ? 1) x>0 2) y<0 2 25 Dec 2007, 10:15
3 If x#-y is (x-y)/(x+y)>1? (1) x>0 (2) y<0 6 23 Jun 2006, 07:17
If x ? -y, is (x-y)/(x+y)>1? 1) x>0 2) y<0 2 12 May 2006, 04:08
x != -y is (x-y)/(x+y)>1? 1. x>0 2. y <0 is there a 6 19 Apr 2006, 15:49
Is x+y >0? 1) x/(x+y)>0 2) y/(x+y)>0 3 12 Feb 2006, 01:42
Display posts from previous: Sort by