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Director
Joined: 03 Jul 2003
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If x + y >0, is x > |y|? (1) x > y (2) y < 0 [#permalink]
 13 Dec 2003, 21:43
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If x + y >0, is x > |y|?
(1) x > y
(2) y < 0
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CEO
Joined: 15 Aug 2003
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kpadma wrote: If x + y >0, is x > |y|?
(1) x > y
(2) y < 0
From stem, We know x> -y
Simply, does x satisfy x >y?
1... is sufficient.
2... not sufficient
A
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VP
Joined: 13 Nov 2003
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we got X>-Y
A tells, X>Y
cool, we know it 's A
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Director
Joined: 14 Oct 2003
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I got A.
1) suffish
2) insuffish
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Director
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If y<0 then from x+y>0 follows that x>-(-Y) or x>y, and x>-y, or x>IyI if y=-5, x=6..IMO should be D..
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Director
Joined: 03 Jul 2003
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Official answer is D
Anyone want to explain why (2) is sufficient ?
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Director
Joined: 28 Oct 2003
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If Y is negative, and added to X to get a positive result, then x must be "bigger" than Y is "small"
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Director
Joined: 28 Oct 2003
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Hey, BG, If you'd like, you can use shift-\, or | to denote absolute value.
It's the key just below backspcae...
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Director
Joined: 14 Oct 2003
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I completely overlooked (2)
Question Stem
X+Y>0 Therefore, X>-Y. Thus, it is unclear if Y is a positive number or a negative number. If Y is a positive number, Then X could be positive or negative. However, if Y is negative then X MUST be positive - given the assumption X>-Y. Number 2 tells us that Y is a negative number. Thus X>-(-Y) = X>|Y|. This is a "Yes/No" question - number 2 allows to answer a definitive "Yes"!
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Manager
Joined: 26 Aug 2003
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kpadma wrote: Official answer is D
Anyone want to explain why (2) is sufficient ?
Statement 2 tells us that y is negative. The statement in the original problem tells us x + y > 0. So if y is negative, according to Stmnt2, then for [x + y > 0] be true x has to be a little more than absolute value of y. And that answers question.
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close
