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If x/y =2/3, then (x-y)/x?

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If x/y =2/3, then (x-y)/x? [#permalink]

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New post 21 Oct 2005, 01:42
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If x/y =2/3, then (x-y)/x?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2
[Reveal] Spoiler: OA
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Re: PS -Toughnut from OG [#permalink]

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New post 21 Oct 2005, 01:54
njss750 wrote:
x/y =2/3, then (x-y)/x?
-1/2, -1/3, 1/3, 1/2, 5/2

Since this was in the last few probs of OG, thot that x/y could also be interpreted as x=-2 and y=-3 and therefore x/y can be equal to 2/3. OG proved me wrong, but is this a theoretical possibility?


we have this law of fraction:
a/b=c/d= (a-c)/(b-d)

x/y=2/3 ---> x/2=y/3= (x-y)/(2-3)=(x-y)/(-1) ---> (x-y)/x= -1/2
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New post 21 Oct 2005, 01:55
hik, i thought too complicatedly :oops: ....you're right, ywilfred! :wink:
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Re: PS -Toughnut from OG [#permalink]

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New post 17 Sep 2013, 19:02
laxieqv wrote:
njss750 wrote:
x/y =2/3, then (x-y)/x?
-1/2, -1/3, 1/3, 1/2, 5/2

Since this was in the last few probs of OG, thot that x/y could also be interpreted as x=-2 and y=-3 and therefore x/y can be equal to 2/3. OG proved me wrong, but is this a theoretical possibility?


we have this law of fraction:
a/b=c/d= (a-c)/(b-d)

x/y=2/3 ---> x/2=y/3= (x-y)/(2-3)=(x-y)/(-1) ---> (x-y)/x= -1/2



will you please explain this rule i couldn't find it anywhere on the internet? also i am not familiar with it either

i have solved it like this:x/y=2/3
x-y/x=x/x-y/x
1-2/3=3-2/3
so the answer is 1/3............. am i right?? :s
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 17 Sep 2013, 19:24
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x/y=2/3, then y/x=3/2.
(x-y)/x = x/x-y/x = 1-3/2 = -1/2
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 18 Sep 2013, 10:52
i got it!!! thanks guys!!!!
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 19 Sep 2013, 03:49
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I solved it like this...

x/y = 2/3
so x = 2 and y = 3
substitute and get the answer -1/2
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 21 Nov 2013, 19:59
I'm still confused. Where does the 1 come from?
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 21 Nov 2013, 21:32
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sdlucas wrote:
I'm still confused. Where does the 1 come from?


You separate out the numerator.

\(\frac{(x-y)}{x} = \frac{x}{x} - \frac{y}{x} = 1 - \frac{y}{x} = 1 - \frac{3}{2} = -\frac{1}{2}\)
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 19 Apr 2016, 16:12
did i get lucky? or can this be a correct approach.

I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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New post 19 Apr 2016, 22:12
ross14 wrote:
did i get lucky? or can this be a correct approach.

I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was


Yes, the approach is fine. You are eliminating one variable, bringing it all in terms of a single variable and then cancelling it off to get a value.
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Re: If x/y =2/3, then (x-y)/x?   [#permalink] 19 Apr 2016, 22:12
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