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If x/y > 2, is 3x + 2y < 18 ? (1) x-y is less than 2

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If x/y > 2, is 3x + 2y < 18 ? (1) x-y is less than 2 [#permalink] New post 20 Apr 2007, 06:54
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If x/y > 2, is 3x + 2y < 18 ?


(1) x-y is less than 2

(2) y-x is is less than 2
Manager
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 [#permalink] New post 20 Apr 2007, 09:47
The answer is E.

If x = 10, y = 11 :: x=1, y = 2

then
1. x-y=-1<2 - not sufficient
2. y-x=1<2 - not sufficient

Taking together not sufficient to answer the question
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Director
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 [#permalink] New post 21 Apr 2007, 04:54
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Stem says x/y > 2, that means x and y both +ve or both -ve

Statement1:
x-y < 2
let x and y both be +ve =====> x > 2y . put it in x - y < 2
2y-y < 2 ====> y < 2
3x+2y = 3(x-y) + 5y
x-y < 2 so 3(x-y) will be < 6
y< 2 so 5y will be < 10
hence 3x+2y will be < 18

let x and y both be -ve
3x+2y will be -ve
hence 3x+2y will be < 18

So statement1 is SUFF

Statement2:
y-x <2

3x+2y = 2(y-x) + 5y

let x and y both be +ve. x=14, y =6 ===> 3x+2y = 54
x = 3, y =1.4 ===> 3x+2y = 11.8
Hence INSUFF


Answer is 'A'
  [#permalink] 21 Apr 2007, 04:54
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If x/y > 2, is 3x + 2y < 18 ? (1) x-y is less than 2

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