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# If x/y > 2, is 3x + 2y < 18 ? (1) x - y is less than

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If x/y > 2, is 3x + 2y < 18 ? (1) x - y is less than [#permalink]  09 Mar 2008, 08:53
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If x/y > 2, is 3x + 2y < 18 ?

(1) x - y is less than 2.
(2) y - x is less than 2.
Current Student
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Re: inequalities [#permalink]  09 Mar 2008, 09:48
I get A..

I will post an answer if correct..
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Re: inequalities [#permalink]  09 Mar 2008, 20:09
bump.

what is the oa ?
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Re: inequalities [#permalink]  09 Mar 2008, 21:14
man, i have no exact way of doing this problem..just plugged numbers..and figured with
statement II
suppose x=18 y=8.1 x/y>2

3x-2y is greater that 18..

suppose x=3 y=0.5 then x/y >2 and 3x-2y will be less than 18..insuff

keep in mind y-x<2 is true in both cases

statement 1) well i just plugged 1 or 2 numbers and kinda feel that the answer is always 3x-2y will always be less than 18..
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Re: inequalities [#permalink]  10 Mar 2008, 00:03
marcodonzelli wrote:
If x/y > 2, is 3x + 2y < 18 ?

(1) x - y is less than 2.
(2) y - x is less than 2.

given that x/y > 2, x and y both are either -ve or +ve.

from 1: x - y < 2.
x < y+2

if both are +ve, x is not greater than y+2.
so if y = 0.5, x should be <2.5. lets say x =2.49
3x + 2y = (3x2.49) + (2x0.5) = 8.498. suff..

if both are -ve, they obviously are less than 18. suff.

(2) y - x < 2

given that x/y > 2, x and y both are either -ve or +ve.

in this case, x could be 20 and y = 5 or x = 3 and y = 1.2.
so not suff.

A is it.
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Re: inequalities [#permalink]  16 Mar 2008, 00:42
GMAT TIGER wrote:
marcodonzelli wrote:
If x/y > 2, is 3x + 2y < 18 ?

(1) x - y is less than 2.
(2) y - x is less than 2.

given that x/y > 2, x and y both are either -ve or +ve.

from 1: x - y < 2.
x < y+2

if both are +ve, x is not greater than y+2.
so if y = 0.5, x should be <2.5. lets say x =2.49
3x + 2y = (3x2.49) + (2x0.5) = 8.498. suff..

if both are -ve, they obviously are less than 18. suff.

(2) y - x < 2

given that x/y > 2, x and y both are either -ve or +ve.

in this case, x could be 20 and y = 5 or x = 3 and y = 1.2.
so not suff.

A is it.

OA is A

argument says that x/y>2. in case y is negative also x must be neg and our thesis is shown. in the case of y<0 there could be differences.

1.if y>0, then x>2x; 3*2y + 2y=8y; if y<2, as 1. says, we would have 8y<16<18. suff
2.in the case of y>0, x>2y and, following 2, y>-2. this adds nothing

therefore oa is A
Re: inequalities   [#permalink] 16 Mar 2008, 00:42
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