If x + y = 8z, then which of the following represents the average

Option B.
Average of x,y and z=>(x+y+z)/3
x+y=8z(given)
Replacing we get,9z/3=3z

Average of x,y,z is (x+y+z)/3=(8z+z)/3=3z

AM of x, y, z = (x+y+z)/3 = (8z+z)/3 = 3z

Correct Option: B

x+y=8z then (x+y+)z/3=(8z+z)/3=9z/3=3z.

We need to determine the average of x, y, and z. In other words:

(x + y + z)/3 = ?

Since x + y = 8z, we can substitute 8z for x + y in our average formula and we have:

(8z + z)/3 = 9z/3 = 3z

Answer: B

To find the average of x, y, and z in terms of z, we can use the formula for the average of three numbers.

The average is found by summing the numbers and then dividing the sum by the count of numbers. In this case, we have x, y, and z.

Given that x + y = 8z, we can rearrange the equation to solve for y:

y = 8z - x.

Now, let's calculate the average of x, y, and z:

Average = (x + y + z) / 3.

Substituting the value of y from the equation above, we have:

Average = (x + (8z - x) + z) / 3.

Simplifying this expression, we get:

Average = (8z + z) / 3.

Combining like terms, we have:

Average = 9z / 3.

Simplifying further, we get:

Average = 3z.

Therefore, the average of x, y, and z in terms of z is (B) 3z.