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If x, y, and k are positive numbers such that 35x/(x-y)

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If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 30 Oct 2012, 11:46
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Question Stats:

52% (03:11) correct 48% (02:05) wrong based on 75 sessions
If x, y, and k are positive numbers such that [35x][/(x-y)] +[(70y-70x)][/(x-y)]=k , and if x>y , which of the following could be a value for k?

(A) −85
(B) −70
(C) −65
(D) −35
(E) −20
[Reveal] Spoiler: OA
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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 30 Oct 2012, 18:59
actleader wrote:
Hi! Could you help with the following... what is the best strategy?
Thanx


If x, y, and k are positive numbers such that [35x][/(x-y)] +[(70y-70x)][/(x-y)]=k , and if x>y , which of the following could be a value for k?

(A) −85
(B) −70
(C) −65
(D) −35
(E) −20

Is the OA correct for this? The ans should be E.
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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 30 Oct 2012, 20:42
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If x, y and k are all +ve numbers, how could k be any of the answer choices??. I can only get k>-35 and so only E satisfies the requirement. But even then, the requirement that k is a postive number is not satisfied.

Kudos Please... If my post helped.
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Status: Done with formalities.. and back..
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Kudos [?]: 426 [0], given: 23

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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 30 Oct 2012, 20:47
MacFauz wrote:
If x, y and k are all +ve numbers, how could k be any of the answer choices??. I can only get k>-35 and so only E satisfies the requirement. But even then, the requirement that k is a postive number is not satisfied.

Kudos Please... If my post helped.

Yup, this question is posted second time on forum... and again its incorrect :shock:
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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 31 Oct 2012, 11:40
MacFauz wrote:
If x, y and k are all +ve numbers, how could k be any of the answer choices??.
Kudos Please... If my post helped.


Great notation, I havn't noticed it initially ))
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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 02 Nov 2012, 11:50
Vips0000 wrote:
MacFauz wrote:
If x, y and k are all +ve numbers, how could k be any of the answer choices??. I can only get k>-35 and so only E satisfies the requirement. But even then, the requirement that k is a postive number is not satisfied.

Kudos Please... If my post helped.

Yup, this question is posted second time on forum... and again its incorrect :shock:


I've brang the question up.
Waiting for the GoGMAT answer.
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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 03 Dec 2012, 10:53
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If number k such that k=35x/(x-y)+(70y-70x)/(x-y) for some positive numbers x and y, and if x>y, which of the following could be a value for k?
-85
-75
-65
-35
-20
Explanation:
First of all simplify expression for k:
k=35x/(x-y)+(70y-70x)/(x-y)=(35x+70y-70x)/(x-y)=(70y-35x)/(x-y)=(35y+35y-35x)/(x-y)=35y/(x-y)-35
Since y>0 and x>y, 35y/(x-y)>0 or 35y/(x-y)-35>0-35 or k>-35.
The answer is E.

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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 20 Sep 2013, 17:27
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actleader wrote:
Hi! Could you help with the following... what is the best strategy?
Thanx


If x, y, and k are positive numbers such that [35x][/(x-y)] +[(70y-70x)][/(x-y)]=k , and if x>y , which of the following could be a value for k?

(A) −85
(B) −70
(C) −65
(D) −35
(E) −20


The easiest way I found is K = 35/[1-Y/X] - 70
35/[1-Y/X] is always >35 [as the denominator is always between 0 and 1]
therefore K>-35, hence K can only be -20

Please give kudos if the explanation helps!! :P
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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 21 Sep 2013, 01:59
Expert's post
actleader wrote:
If x, y, and k are positive numbers such that [35x][/(x-y)] +[(70y-70x)][/(x-y)]=k , and if x>y , which of the following could be a value for k?

(A) −85
(B) −70
(C) −65
(D) −35
(E) −20


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Re: If x, y, and k are positive numbers such that 35x/(x-y) [#permalink] New post 24 Jun 2015, 03:24
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Re: If x, y, and k are positive numbers such that 35x/(x-y)   [#permalink] 24 Jun 2015, 03:24
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