If x, y, and z are 3 positive consecutive integers such that

Oldest

Best Reply

Author

Message

TAGS:

Senior Manager

Joined: 04 Nov 2006

Posts: 269

Location: California

Followers: 1

Kudos [?]: 3 [0], given: 0

If x, y, and z are 3 positive consecutive integers such that [#permalink]

20 Dec 2006, 15:32

00:00

Question Stats:

0% (00:00) correct

0% (00:00) wrong

based on 0 sessions

If x, y, and z are 3 positive consecutive integers such that x < y < z, what is the remainder when the product of x, y, and z is divided by 8?

(1) (xz)^2 is even

(2) 5 . y^3 is odd

Senior Manager

Joined: 08 Jun 2006

Posts: 347

Location: Washington DC

Followers: 1

Kudos [?]: 5 [0], given: 0

Re: DS_If x, y, and z are 3 positive consecutive... [#permalink]

20 Dec 2006, 16:35

mm007 wrote:

If x, y, and z are 3 positive consecutive integers such that x < y < z, what is the remainder when the product of x, y, and z is divided by 8?

(1) (xz)^2 is even

(2) 5 . y^3 is odd

Going for D here ... wait for OA though

From 1) possible cases - (x even, z even) or (x even, z odd) or (x odd, z even)
But from the question stem ...x < y < z , here x and z are both either even or odd.
so only even possible ..that means multiple of 8

From 2) y ^3 has to be odd..so y odd ..so x and z are even...divisible by 8

Director

Joined: 30 Nov 2006

Posts: 598

Location: Kuwait

Followers: 8

Kudos [?]: 115 [0], given: 0

[#permalink]

20 Dec 2006, 17:54

I would go for D

question gives: x<y<z and x,y,z and consecutive ints.

question asks: remainder if xyz/8 ?

Statement 1 : (XZ)^ 2 is even
------------------------------------
from the question, x and z : either both even or both odd
XZ * XZ is even so XZ must be even --> x and z both are even
therefore, y is odd

since the product xyz consists of two even factors, it must be divisible by 2 and also by 4 --> it is divisible by 8

Statement 1 is sufficient

Statement 2: 5 y^3 is odd
--------------------------------
5 is odd --> y^3 must be odd
so, y also must be odd
if y is odd, then x and z are even integers
for the same reasoning in statement 1, the product xyz is divisible by 8

Statement 2 is sufficient

Answer is D

Director

Joined: 17 Jul 2006

Posts: 718

Followers: 1

Kudos [?]: 8 [0], given: 0

[#permalink]

22 Dec 2006, 10:22

D is the answer.

A gives the info. that x and Z are even and so Y is odd

B gives the info that Y is odd and so the other integers must be even. since they are consecutive integers.

[#permalink] 22 Dec 2006, 10:22

		Similar topics	Author	Replies	Last post
Similar Topics:		If x, y, and z are 3 positive consecutive integers such that	rxs0005	3	23 Sep 2006, 05:50
		Is z equal to the median of 3 positive integers x, y and z?	sujayb	3	21 Nov 2006, 23:20
		x , y , and z are integers. Are they consecutive? 1. y	amitdgr	3	03 Oct 2008, 00:49
		If x, y, and z are consecutive even positive integers, which	banksy	1	01 Mar 2011, 10:56
	1	Are the positive integers x and y consecutive?	daviesj	3	06 Jan 2013, 08:04

If x, y, and z are 3 positive consecutive integers such that

Main navigation

GMAT Resources

Partners

MBA Resources

GMAT ® is a registered trademark of the Graduate Management Admission Council ® (GMAC ®). GMAT Club's website has not been reviewed or endorsed by GMAC.

GMAT Courses

Admissions Consulting

If x, y, and z are 3 positive consecutive integers such that

If x, y, and z are 3 positive consecutive integers such that

Main navigation

GMAT Resources

Partners

MBA Resources