Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 22 Sep 2014, 10:36

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x, y, and z are 3 positive consecutive integers such that

 Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
Senior Manager
Joined: 04 Nov 2006
Posts: 267
Location: California
Followers: 1

Kudos [?]: 22 [0], given: 0

If x, y, and z are 3 positive consecutive integers such that [#permalink]  20 Dec 2006, 14:32
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:03) correct 0% (00:00) wrong based on 1 sessions
If x, y, and z are 3 positive consecutive integers such that x < y < z, what is the remainder when the product of x, y, and z is divided by 8?

(1) (xz)^2 is even

(2) 5 . y^3 is odd
Senior Manager
Joined: 08 Jun 2006
Posts: 343
Location: Washington DC
Followers: 1

Kudos [?]: 14 [0], given: 0

Re: DS_If x, y, and z are 3 positive consecutive... [#permalink]  20 Dec 2006, 15:35
mm007 wrote:
If x, y, and z are 3 positive consecutive integers such that x < y < z, what is the remainder when the product of x, y, and z is divided by 8?

(1) (xz)^2 is even

(2) 5 . y^3 is odd

Going for D here ... wait for OA though

From 1) possible cases - (x even, z even) or (x even, z odd) or (x odd, z even)
But from the question stem ...x < y < z , here x and z are both either even or odd.
so only even possible ..that means multiple of 8

From 2) y ^3 has to be odd..so y odd ..so x and z are even...divisible by 8
Director
Joined: 30 Nov 2006
Posts: 592
Location: Kuwait
Followers: 11

Kudos [?]: 154 [0], given: 0

[#permalink]  20 Dec 2006, 16:54
I would go for D

question gives: x<y<z and x,y,z and consecutive ints.

question asks: remainder if xyz/8 ?

Statement 1 : (XZ)^ 2 is even
------------------------------------
from the question, x and z : either both even or both odd
XZ * XZ is even so XZ must be even --> x and z both are even
therefore, y is odd

since the product xyz consists of two even factors, it must be divisible by 2 and also by 4 --> it is divisible by 8

Statement 1 is sufficient

Statement 2: 5 y^3 is odd
--------------------------------
5 is odd --> y^3 must be odd
so, y also must be odd
if y is odd, then x and z are even integers
for the same reasoning in statement 1, the product xyz is divisible by 8

Statement 2 is sufficient

Answer is D
Director
Joined: 17 Jul 2006
Posts: 716
Followers: 1

Kudos [?]: 8 [0], given: 0

[#permalink]  22 Dec 2006, 09:22
D is the answer.

A gives the info. that x and Z are even and so Y is odd

B gives the info that Y is odd and so the other integers must be even. since they are consecutive integers.
[#permalink] 22 Dec 2006, 09:22
Similar topics Replies Last post
Similar
Topics:
10 If y is the sum of x consecutive positive integers, and x>3, 5 24 Mar 2014, 14:34
2 Are the positive integers x and y consecutive? 3 06 Jan 2013, 07:04
If x, y, and z are consecutive even positive integers, which 2 01 Mar 2011, 09:56
x , y , and z are integers. Are they consecutive? 1. y 3 02 Oct 2008, 23:49
If x, y, and z are 3 positive consecutive integers such that 3 23 Sep 2006, 04:50
Display posts from previous: Sort by

# If x, y, and z are 3 positive consecutive integers such that

 Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.