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# If x, y, and z are consecutive integers such that x > y > z

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Senior Manager
Joined: 28 Dec 2010
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Kudos [?]: 98 [0], given: 33

If x, y, and z are consecutive integers such that x > y > z [#permalink]  21 Jul 2013, 07:55
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Question Stats:

55% (02:45) correct 45% (01:15) wrong based on 112 sessions
If x, y, and z are consecutive integers such that x > y > z and the sum of x, y, and z is a multiple of 10, which of the following could be the value of x?

A. 0
B. 1
C. 9
D. 10
E. 12

[Reveal] Spoiler:
Guys I think 2 answers are correct. What do you come up with?
[Reveal] Spoiler: OA

Last edited by Bunuel on 21 Jul 2013, 08:19, edited 1 time in total.
Edited the question.
Math Expert
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Posts: 29679
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Kudos [?]: 53122 [0], given: 8043

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  21 Jul 2013, 08:19
Expert's post
vibhav wrote:
If x, y, and z are consecutive integers such that x > y > z and the sum of x, y, and z is a multiple of 10, which of the following could be the value of x?

A. 0
B. 1
C. 9
D. 10
E. 12

[Reveal] Spoiler:
Guys I think 2 answers are correct. What do you come up with?

Given that $$z + y +x = (y-1) + y + (y+1) = 3y = 10k$$ --> $$y$$ is a multiple of 10 --> $$x = y+1$$, so x is a multiple of 10 plus 1. Only answer choices B fits: $$z=-1$$, $$y=0$$, and $$z=1$$ --> $$z+y+x=0$$.

Else you could simply plug-in values for x in (x-2) + (x-1) + x and see which one yields a multiple of 10.
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Senior Manager
Joined: 28 Dec 2010
Posts: 335
Location: India
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Kudos [?]: 98 [0], given: 33

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  21 Jul 2013, 08:53
Bunuel why can't it be 11,10,9 totals to 30 which is divisible by 10?
Math Expert
Joined: 02 Sep 2009
Posts: 29679
Followers: 4889

Kudos [?]: 53122 [0], given: 8043

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  21 Jul 2013, 08:54
Expert's post
vibhav wrote:
Bunuel why can't it be 11,10,9 totals to 30 which is divisible by 10?

Yes, x could be 11, but 11 is not among the options.
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Kudos [?]: 82 [0], given: 0

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  15 Dec 2014, 04:01
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Kudos [?]: 1045 [1] , given: 58

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  23 Dec 2014, 10:20
1
KUDOS
Expert's post
Hi All,

This question can be easily beaten by a bit of "brute force" and TESTing THE ANSWERS.

We're given a very specific set of restrictions in this prompt:
1) X, Y and Z are CONSECUTIVE INTEGERS
2) X > Y > Z
3) X+Y+Z = a multiple of 10

We're asked which of the 5 answer COULD be the value of X given these restrictions. Rather than staring at the screen or doing layered math, we can "brute force" the answers until we find one that fits these restrictions..

In this case, the numbers would be 0, -1, and -2. The sum = -3 which is NOT a multiple of 10. Eliminate A.

In this case, the numbers would be 1, 0, and -1. The sum = 0 which IS a multiple of 10. B IS the answer.

[Reveal] Spoiler:
B

For the sake of argument, if you did not immediately realize that 0 is a multiple of 10, then you could quickly TEST the remaining 3 options and quickly disprove them.

GMAT assassins aren't born, they're made,
Rich
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GMAT Date: 02-11-2015
WE: Psychology and Counseling (Other)
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Kudos [?]: 59 [0], given: 169

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  25 Dec 2014, 08:20
I did it this way, which might be a bit similar in a way:

1) Since they are consecutive integers, these could be: x, x-1, x-2 (x>y>z)

2) I added them to give 0 (the 1st multiple of 10, if we say that they add up to 0*Unckown value):
x+x-1+x-2=0
3x-3=0
3x=3
x=3/3
EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
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Location: United States (CA)
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GRE 1: 340 Q170 V170
Followers: 167

Kudos [?]: 1045 [0], given: 58

Re: If x, y, and z are consecutive integers such that x > y > z [#permalink]  25 Dec 2014, 09:42
Expert's post
Hi pacifist85,

Your approach works here, but ONLY because 0 is the multiple of 10 that is involved in the correct answer. If it was any other multiple of 10, then you would have only gotten the solution by "brute forcing" your equation into every possible multiple of 10.

eg.

3x - 3 = 10
3x - 3 = 20
3x - 3 = 30
Etc.

Since these answer choices in this question are all relatively small, even if you did have to brute force multiple possibilities, you would have gotten to the answer relatively quickly, so I think that your approach is fine. In the end, I measure any approach by 2 things:

1) Did it get you the correct answer.
2) Were you able to complete the question relatively quickly (for that prompt).

If the answer to both questions is YES, then you did well.

GMAT assassins aren't born, they're made,
Rich
_________________

Re: If x, y, and z are consecutive integers such that x > y > z   [#permalink] 25 Dec 2014, 09:42
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