If x, y and z are integers greater than 1, what is the value : DS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 23 Jan 2017, 20:42

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x, y and z are integers greater than 1, what is the value

Author Message
Senior Manager
Joined: 07 Jan 2008
Posts: 412
Followers: 3

Kudos [?]: 219 [0], given: 0

If x, y and z are integers greater than 1, what is the value [#permalink]

### Show Tags

09 Jun 2008, 06:43
00:00

Difficulty:

(N/A)

Question Stats:

100% (03:01) correct 0% (00:00) wrong based on 2 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x, y and z are integers greater than 1, what is the value of x + y + z?
1) xyz = 70
2) x/yz = 7/10
Manager
Joined: 19 May 2008
Posts: 52
Followers: 0

Kudos [?]: 5 [0], given: 0

### Show Tags

09 Jun 2008, 06:48
1) xyz = 70
decompose 70 into its prime factors: 70 = 2 x 5 x 7
this is the only product of 3 integers greater than 1 that gives 70
=> x+y+z = 2+5+7 = 14
=> 1) is sufficient

2) x/zy = 7/10
doesn't say much about x, y and z. Take any x, y and z that satisfy the equation above, multiply x by a number and z or y by the same number you would still have the equality above but a different sum.
=> 2 is not sufficient

Manager
Joined: 27 Apr 2008
Posts: 110
Followers: 1

Kudos [?]: 12 [0], given: 0

### Show Tags

09 Jun 2008, 07:03

SVP
Joined: 30 Apr 2008
Posts: 1887
Location: Oklahoma City
Schools: Hard Knocks
Followers: 40

Kudos [?]: 571 [0], given: 32

### Show Tags

09 Jun 2008, 07:23
The question stem says "integers greater than 1". 1 is not greater than 1. It would be possible if the question asked for positive integers, or integers >= 1, etc. But the way it is written, 1 is not an option.

Why wouldn't D be the answer, "Both statements independently are sufficient to answer the question."

If xyz = 70 is sufficient, and then #2 says $$\frac{x}{yz}=\frac{7}{10}$$

#2 is saying the same thing as #1. It tells you the value of x = 7. and yz = 10. The only possible integers > 1 with product of 10 is 2 & 5. #2 is sufficient as well.

j allen morris
rino wrote:

_________________

------------------------------------
J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$. GMAT Club Premium Membership - big benefits and savings Manager Joined: 19 May 2008 Posts: 52 Followers: 0 Kudos [?]: 5 [0], given: 0 Re: DS: GMATPrep xyz [#permalink] ### Show Tags 09 Jun 2008, 13:09 Correct. 1 is not "greater than 1". x/yz = 7 / 10 doesn't say anything about the values of x, y and z. Here's an example: x = 7, y = 2, z = 5 sum = 14 x/yz = 7 / (2x5) = 7 / 10 => fine now pick x = 70, y = 2, z = 50 (notice i multiplied x and z by 10... which would be later on simplified) sum = 122 x/yz = 70 / (2x50) = 70/100 = 7 / 10 jallenmorris wrote: The question stem says "integers greater than 1". 1 is not greater than 1. It would be possible if the question asked for positive integers, or integers >= 1, etc. But the way it is written, 1 is not an option. Why wouldn't D be the answer, "Both statements independently are sufficient to answer the question." If xyz = 70 is sufficient, and then #2 says $$\frac{x}{yz}=\frac{7}{10}$$ #2 is saying the same thing as #1. It tells you the value of x = 7. and yz = 10. The only possible integers > 1 with product of 10 is 2 & 5. #2 is sufficient as well. Answer D j allen morris rino wrote: what about 1*14*5 or 10*1*7 the answer is E CEO Joined: 29 Mar 2007 Posts: 2583 Followers: 19 Kudos [?]: 422 [1] , given: 0 Re: DS: GMATPrep xyz [#permalink] ### Show Tags 09 Jun 2008, 13:18 1 This post received KUDOS lexis wrote: If x, y and z are integers greater than 1, what is the value of x + y + z? 1) xyz = 70 2) x/yz = 7/10 A. 1: only can be 7,2,5 2: could be 7/(2*5) or 14/(2*10) Current Student Joined: 28 Dec 2004 Posts: 3384 Location: New York City Schools: Wharton'11 HBS'12 Followers: 15 Kudos [?]: 283 [0], given: 2 Re: DS: GMATPrep xyz [#permalink] ### Show Tags 09 Jun 2008, 13:29 i too Get A.. 2) is insuff because x/yz=7/10 can easily be x=14, yz=20... or x=7 yz=10 SVP Joined: 30 Apr 2008 Posts: 1887 Location: Oklahoma City Schools: Hard Knocks Followers: 40 Kudos [?]: 571 [0], given: 32 Re: DS: GMATPrep xyz [#permalink] ### Show Tags 09 Jun 2008, 13:44 GMATBLACKBELT, Good call on that. I wasn't think of having to reduce x/yz to get 7/10. I was taking what they gave us and not thinking beyond that. That's a mistake on the GMAT (as long as we don't over-think it;)) _________________ ------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

GMAT Club Premium Membership - big benefits and savings

Senior Manager
Joined: 07 Jan 2008
Posts: 412
Followers: 3

Kudos [?]: 219 [0], given: 0

### Show Tags

12 Jun 2008, 04:03
Correct. 1 is not "greater than 1".
x/yz = 7 / 10 doesn't say anything about the values of x, y and z.

Here's an example:
x = 7, y = 2, z = 5
sum = 14
x/yz = 7 / (2x5) = 7 / 10 => fine

now pick
x = 70, y = 2, z = 50 (notice i multiplied x and z by 10... which would be later on simplified)
sum = 122
x/yz = 70 / (2x50) = 70/100 = 7 / 10

jallenmorris wrote:
The question stem says "integers greater than 1". 1 is not greater than 1. It would be possible if the question asked for positive integers, or integers >= 1, etc. But the way it is written, 1 is not an option.

Why wouldn't D be the answer, "Both statements independently are sufficient to answer the question."

If xyz = 70 is sufficient, and then #2 says $$\frac{x}{yz}=\frac{7}{10}$$

#2 is saying the same thing as #1. It tells you the value of x = 7. and yz = 10. The only possible integers > 1 with product of 10 is 2 & 5. #2 is sufficient as well.

j allen morris
rino wrote:

OA is A.
Re: DS: GMATPrep xyz   [#permalink] 12 Jun 2008, 04:03
Display posts from previous: Sort by