If x, y, and z are positive integers and 3x = 4y = 7z, then : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 17 Jan 2017, 03:33

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x, y, and z are positive integers and 3x = 4y = 7z, then

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Director
Joined: 05 Feb 2006
Posts: 898
Followers: 3

Kudos [?]: 107 [0], given: 0

If x, y, and z are positive integers and 3x = 4y = 7z, then [#permalink]

### Show Tags

19 Oct 2006, 09:33
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x, y, and z are positive integers and 3x = 4y = 7z, then the least possible value of x + y + z is

(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Senior Manager
Joined: 13 Jul 2006
Posts: 330
Followers: 1

Kudos [?]: 10 [0], given: 0

### Show Tags

19 Oct 2006, 10:04
The answer should be a (D).The LCM of (3,4,7) will be the least number when all three will be equal which happens when
x=28
y=21
z=12

The sum of all three is 61.
_________________

A well-balanced person is one who has a drink in each of his hands.

Manager
Joined: 31 Aug 2006
Posts: 213
Followers: 1

Kudos [?]: 2 [0], given: 0

### Show Tags

19 Oct 2006, 10:07
3x = 4y = 7z
Henec y=3*x/4 , z= 3*x/7
Hence x+y+z = 61*x/28.Hence answer has to be a multiple of 61.Which is (D)
Director
Joined: 05 Feb 2006
Posts: 898
Followers: 3

Kudos [?]: 107 [0], given: 0

### Show Tags

19 Oct 2006, 10:34
sangarelli wrote:
The answer should be a (D).The LCM of (3,4,7) will be the least number when all three will be equal which happens when
x=28
y=21
z=12

The sum of all three is 61.

and how do you come up with those numbers? pick numbers? It would be time consuming....
Manager
Joined: 04 Oct 2006
Posts: 189
Followers: 1

Kudos [?]: 1 [0], given: 0

### Show Tags

19 Oct 2006, 12:16
No you just find the least common multiple of 3, 4, and 7 (which is 28) and then solve each equation and add.
Director
Joined: 05 Feb 2006
Posts: 898
Followers: 3

Kudos [?]: 107 [0], given: 0

### Show Tags

19 Oct 2006, 12:33
Got it at last I am slow

Had to clarify what the Least Common Multiple means in my language... Another gap in my knowledge was repaired , that is good
Senior Manager
Joined: 13 Sep 2006
Posts: 281
Location: New York
Followers: 1

Kudos [?]: 17 [0], given: 0

### Show Tags

19 Oct 2006, 12:50
burningskulls wrote:
No you just find the least common multiple of 3, 4, and 7 (which is 28) and then solve each equation and add.

Least common multiple cannot be 28...as 3 is not divisible by 28.

You need to find the least common multiple of 3, 4, 7 whch is 84 and then you get

x=28
y=21
z=12

= 61
_________________

"Never let the fear of striking out get in your wayâ€

Senior Manager
Joined: 01 Sep 2006
Posts: 301
Location: Phoenix, AZ, USA
Followers: 1

Kudos [?]: 26 [0], given: 0

Easier method to solve this [#permalink]

### Show Tags

20 Oct 2006, 11:27
3x = 4y = 7z
Thus will only work when 3 numbers are not divisioble by each other

x will be min 4*7=28
y will be 3*7=21
z will be 3*4=12

If the numbers where divisble by even 1 other number

LCM would be better way to go
Easier method to solve this   [#permalink] 20 Oct 2006, 11:27
Display posts from previous: Sort by

# If x, y, and z are positive integers and 3x = 4y = 7z, then

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.