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If x, y and z are positive integers, is x% of y bigger than [#permalink]
 20 Jul 2009, 10:24
Question Stats:
71% (01:47) correct
28% (00:54) wrong based on 1 sessions
If x, y and z are positive integers, is x% of y bigger than y% of Z? (1) x= z (2) z –y = y - x What not B is also ans.
Because statement B says x<y<z, so the statement is enough to ans the statement. |
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Re: GMat club test M11 doubt [#permalink]
20 Jul 2009, 10:30
No where is it mentioned,nor can you deduce that x < y < z,
Stmt B says Z –y = y - x
which means y is equidistant from x and z
could be
z.................y..............x
or
x............y................z
So InSUFF
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Re: GMat club test M11 doubt [#permalink]
16 Sep 2012, 18:30
How is it possible that Z-Y=Y-X if X=Z according to (1)? I read somewhere 1 and 2 can't conflict on DS questions If z and x are equal, you'd get a negative on one side of the equation and a positive on the other side... Just saying (1) x=z conflicts with (2) z - y = y- x unless they are all zero, but that isn't possible since the question says they're positive. skpMatcha wrote: No where is it mentioned,nor can you deduce that x < y < z,
Stmt B says Z –y = y - x
which means y is equidistant from x and z
could be
z.................y..............x
or
x............y................z
So InSUFF
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Re: If x, y and z are positive integers, is x% of y bigger than [#permalink]
16 Sep 2012, 19:21
 Probably this approach of solving the question should help you understand: x% of y is bigger than y% of z essentially question is asking whether xy >yz or xy-yz >0 or y(x-z) >0 ? ->Lets call it 'The question statement' or TQS We know that x, y and z are positive integers. Therefore y >0 and hence we would be able to answer if we know about (x-z) [Sign or Value either should do] 1. x=z Putting in TQS we can see y(x-z) = y* 0 = 0. so we know the relation x% y = y% z. Therefore SUFFICIENT 2. z-y = y-x or (z+x) =2Y So we know z+x is positive (But we already knew it since X and Z both are positive) However we still do not know about x-z. Therefore we do not know about TQS. Therefore , INSUFFICIENT. So Ans is "A"
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Re: GMat club test M11 doubt [#permalink]
17 Sep 2012, 05:00
ctiger100 wrote: How is it possible that Z-Y=Y-X if X=Z according to (1)? I read somewhere 1 and 2 can't conflict on DS questions
The statements are not contradictory here; they can both be true if x=y=z. For example, if x = y = z = 6, you'll find that both statements are true, and these values agree with the restrictions in the question itself.
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Re: If x, y and z are positive integers, is x% of y bigger than [#permalink]
17 Sep 2012, 05:53
Answer is A. Question is (X/100)Y > (Y/100)Z --> Is X>Z ? Statement 1 Directly states that X=Z, so X is not greater than Z. Statement 2 Y=(X+Z)/2 ---> We just get to know that Y is the midpoint of X & Z. Magnitude of either X or Z is not known.
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Re: GMat club test M11 doubt [#permalink]
17 Sep 2012, 06:10
Great, thats what I was looking for, appreaciate the answer. Thanks! IanStewart wrote: ctiger100 wrote: How is it possible that Z-Y=Y-X if X=Z according to (1)? I read somewhere 1 and 2 can't conflict on DS questions
The statements are not contradictory here; they can both be true if x=y=z. For example, if x = y = z = 6, you'll find that both statements are true, and these values agree with the restrictions in the question itself. |
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Re: If x, y and z are positive integers, is x% of y bigger than [#permalink]
26 Sep 2012, 07:25
vaivish1723 wrote: If x, y and z are positive integers, is x% of y bigger than y% of Z? (1) x= z (2) z –y = y - x What not B is also ans.
Because statement B says x<y<z, so the statement is enough to ans the statement. The question asks: is \frac{x}{100}*y>\frac{y}{100}*z? --> Since y is a positive integer we can safely reduce by \frac{y}{100} and the question becomes: is x>z? Notice that the answer to the question does not depend on the value of y.(1) x=z. Answer to the question is NO. Sufficient. (2) z-y=y-x --> x+z=2y. Clearly insufficient to say whether x>z. Answer: A.
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Re: If x, y and z are positive integers, is x% of y bigger than
[#permalink]
26 Sep 2012, 07:25
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