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From stmt 1:
factors of 57 are 1,3,19,57
For x and y to be prome numbers and their sum to be any of these
x has to be 2 and y has to 17.
We don't know anything about z.
INSUFF

From stmt 2:
Z is 1 or 3 or 19 or 57.
INSUFF

Combining:
Z can not be 1 or 3.(x and y are prime and they are less than z)
2 is not a factor of 19 or 57.

So C.

One question though,
It is time consuming to find whether 57 is the sum of any prime numbers.
I had to pick the primes below 57 and find out whether 2 primes can sum up to 57.
Is there any easy way?

Question gives: x < y < z, each is +int
z is odd +int

Question asks: is X factor of Z ? [ does X*K = Z, K:+int ]

Statement 1: X & Y are prime and X+Y factor of 57
-----------------------------------------------------------
57 is a prime number --> x+y =1 or 57
since x and y are each +tive int., then neither x nor y can be zero
Therefore, x+y = 57

this leads us to nothing as I know nothing about z
Note: you don't really need to find what X and Y are

Statement 2: Z is a factor of 57
--------------------------------------
57 is prime, Z can not be 1 because z>y>z and non of x and y can be zero or negative
So Z = 57
Yet, this tells us nothing about x and y

Statements 1 and 2
-----------------------
from 2, z = 57 and the only factors of 57 are 1 and 57
from question, neither x nor y can be zero or 1
from statement 1, neither x nor y can be 57
So, X is NOT a factor of Z

Thus, the answer is C

Is it helpful, the way I expain ? or is too much details and too confusing ?

there is an easy way to verify that 57 is not the sum of primes...
for a sum of two numbers to be odd - one must be even and one odd. if these are primes then the even number must be 2 and the odd must be 55 which is not a prime ... hence no solution to that. no need to pick numbers.

exactly , no way sum of two primes can equate 57. if x + y = 57, then one of them has to be even, and the only even prime is 2.
==> y has to be 55 which is not prime.

Re: DS_If x, y, and z are positive integers... [#permalink]
27 May 2012, 00:55

4

This post received KUDOS

Swagatalakshmi wrote:

mm007 wrote:

If x, y, and z are positive integers such that x < y < z, is x a factor of the odd integer z?

(1) x and y are prime numbers, whose sum is a factor of 57

(2) z is a factor of 57

57 has following factors 1,3, 19, 57

From (1) :

x+y =3 if x =1 then x is not prime x+y =19 Therefore x=2, y=17 x+y =57 can't be expressed as sum of two prime numbers.

Answer is A. Since x has to be 2, and it is given in the question that z is an odd integer. Thus we know that 2 cannot be the factor of an odd integer.

Re: If x, y, and z are positive integers such that x < y < z [#permalink]
27 May 2012, 03:57

8

This post received KUDOS

Expert's post

5

This post was BOOKMARKED

If x, y, and z are positive integers such that x < y < z, is x a factor of the odd integer z?

Notice that we are told that z is an odd number.

(1) x and y are prime numbers, whose sum is a factor of 57 --> factors of 57 are 1, 3, 19 and 57. Since we are told that x and y are prime numbers then x can only be 2 and y can only be 17 (x+y=19). x=2=even cannot be a factor of the odd integer z. Sufficient.

(2) z is a factor of 57. Clearly insufficient as we have no info about x.

Re: If x, y, and z are positive integers such that x < y < z [#permalink]
09 Feb 2014, 04:53

1

This post received KUDOS

A is the answer.

Z is odd from question stem.

statement 1 says x & y are primes whose sum is a factor of 57. First lets deduce factors of 57.

57 = 1 * 57 = 3 * 19

so x+y must be equal to one of these factors. x+y cannot be equal to 1 or 3 since x & y are positive prime integers.

we have x+y=57 or x+y = 19. Lets take x+y=57 for this to happen one of the x & y must be even and remember both must be prime so only even prime is 2. if x=2 then y will be 55 and not prime so x+y = 57 is ruled out.

taking what is left. x+y=19 and using same logic as above x has to be 2. and y=17 hence both are prime and sum is factor of 57. Going back to the question, is x a factor of odd integer z? NO x=2 it cannot be. Sufficient!

Statement 2 is clearly insufficient. no information about x. _________________

Re: If x, y, and z are positive integers such that x < y < z, is x a facto [#permalink]
11 Nov 2014, 23:55

If x, y, and z are positive integers such that x < y < z, is x a factor of the odd integer z?

(1) x and y are prime numbers, whose sum is a factor of 57

(2) z is a factor of 57

Statement 1: Factors of 57 = 3 * 19 Therefore X, Y, Z could be: 1, 2, 3 >> Yes 2, 17, 19 >> No INSUFFICIENT

Statement 2: z is a factor of 57, meaning z is either 3 or 19 However, we don't know anything about x INSUFFICIENT

Statements 1+2: If x+y is 3 or 19 and z is 3 or 19 The numbers could be: 1, 18, 19 >> Yes (because 1 is a factor of 19) 1, 2, 3 >> Yes (because 1 is a factor of 3) 8, 11, 19 >> No INSUFFICIENT

Re: If x, y, and z are positive integers such that x < y < z, is x a facto [#permalink]
12 Nov 2014, 00:05

kthxbye wrote:

If x, y, and z are positive integers such that x < y < z, is x a factor of the odd integer z?

(1) x and y are prime numbers, whose sum is a factor of 57

(2) z is a factor of 57

Statement 1: Factors of 57 = 3 * 19 Therefore X, Y, Z could be: 1, 2, 3 >> Yes 2, 17, 19 >> No INSUFFICIENT

Statement 1 also says that x and y are prime numbers. 1 is not a prime. It's always a No with statement 1 and hence is sufficient. Will post detailed solution tonight.

Please press Kudos if you find the question helpful!

Re: If x, y, and z are positive integers such that x < y < z [#permalink]
12 Nov 2014, 03:18

Hi,

Statement 1: x and y are prime numbers, whose sum is a factor of 57

57= 1 x 57 & 57= 3 x 19 Factors are 1, 3, 19, 57 1, 3 and 57 cannot be the sum!! ( 3 = 2+1 but 1 is not a prime number; try any combination for 57, it will always be the sum of an even integer and odd integer and 2 is the only even prime number. So you cannot have 57 as the sum of two prime numbers!!!)

So the sum should be 19 and 19 = 2 + 17 is the only way you can write it as a sum of two prime numbers.

So the numbers are x,y, z which is 2,17, an odd integer!! Now ask the question : Is x a factor of odd integer z? The answer is No for sure. Hence Statement 1 alone is sufficient!!

Statement 2 alone doesn't tell you anything about x, so you cannot say that x is a factor of 57!!

Correct answer would be A _________________

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Kindly press Kudos if the explanation is clear. Thank you Ambarish

Re: If x, y, and z are positive integers such that x < y < z [#permalink]
22 May 2015, 23:29

1

This post was BOOKMARKED

Nayan wrote:

One question though, It is time consuming to find whether 57 is the sum of any prime numbers. I had to pick the primes below 57 and find out whether 2 primes can sum up to 57. Is there any easy way?

57 is an odd number.. All prime numbers are odd except 2 ..therefore ODD+ODD=ODD is not possible only possibility to check is 57=2+prime numb (which in this case is not possible)

This is the fastest way to do it.. Hope this Helps!

gmatclubot

Re: If x, y, and z are positive integers such that x < y < z
[#permalink]
22 May 2015, 23:29

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