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If x, y, and z are positive numbers, is x>y>z?

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If x, y, and z are positive numbers, is x>y>z? [#permalink] New post 01 Oct 2012, 12:00
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88% (01:37) correct 12% (00:15) wrong based on 25 sessions
If x, y, and z are positive numbers, is x>y>z?

(1) xz > yz
(2) yx > yz
[Reveal] Spoiler: OA

Last edited by Bunuel on 02 Oct 2012, 02:10, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Verbal Quant 2nd ed.: Data Sufficieny Ques 69 [#permalink] New post 01 Oct 2012, 12:03
1 gives x>y (cancelling z as it is not equal to 0) Not sufficient
2 gives x>z (cancelling y as it is not equal to 0) Not sufficient

even when combined we dont know the relation b/w y and z
it could be y>z or y<z

so E
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Re: Verbal Quant 2nd ed.: Data Sufficieny Ques 69 [#permalink] New post 01 Oct 2012, 12:06
Posting my reply to this question:

Official answer doesn't look correct to me. Here is how I solved the problem.
1st statement tells me x>y
2nd statement tells me x>z

Still, need to determine between y and z which is greater? Official answer says can't be determined but this can be solved by combining the 2 equations.

xz - yx > yz - yz
x (z-y) > 0
, therefore z > y since x > 0

The answer should be C
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Re: Verbal Quant 2nd ed.: Data Sufficieny Ques 69 [#permalink] New post 01 Oct 2012, 12:09
Just realized, ignore the previous post. Second statement is being subtracted so the inequality sign should flip for that statement 2.

Official answer is correct.
Re: Verbal Quant 2nd ed.: Data Sufficieny Ques 69   [#permalink] 01 Oct 2012, 12:09
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