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If x, y, and z are three-digit positive integers and if x = [#permalink]
18 Sep 2012, 08:10

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Difficulty:

65% (hard)

Question Stats:

55% (02:08) correct
45% (01:30) wrong based on 369 sessions

If x, y, and z are three-digit positive integers and if x = y + z, is the hundreds digit of x equal to the sum of the hundreds digits of y and z ?

(1) The tens digit of x is equal to the sum of the tens digits of y and z. (2) The units digit of x is equal to the sum of the units digits of y and z.

Is it safe to conclude that the place value of an integer number (represented as a sum of different integers), depends upon only the preceding place value of integers being summed up?

for eg: x=1000a+100b+10c+1d y=1000e+100f+10g+1h z=1000l+100m+10n+1p if z=x+y then

is l only dependent upon value of b and f or some other parameters also??

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
18 Sep 2012, 10:06

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Let x= a b c y = d e f z= g h i

x= y+z

1 --> b= e+h which in turn implies c=f+i and so a=d+g (and this implies there is no carry forward in the addition of units and tens place digit of the two numbers)

2--> c=f+i which does not tell us if b= e+h(as there could be a carry forward bcos of this addition to the hundred place)

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
19 Sep 2012, 23:12

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x = ABC y = DEF z = GHI

DEF +GHI _____ ABC

Question: Is D + G = A? This is true if there is no carry-over from the tens digits' sum.

1. E + H = B, This means there is no carry over to hundreds position. SUFFICIENT. 2. C + F = I, This means there is no carry over to tens position BUT we do not know if there will be a carry over during the sum of tens. INSUFFICIENT.

Answer: A _________________

Impossible is nothing to God.

Last edited by mbaiseasy on 15 Jan 2013, 00:23, edited 1 time in total.

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
13 Apr 2013, 10:27

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mokura wrote:

my confusion is the following regarding (1). maybe i am not reading the question right, but assume the following:

y: 6 4 3 z: 4 4 2

x: 1 0 8 5

so, the tens digit of x is equal to the sum of the tens digit of y + z. however, the hundreds digit, 6 + 4 = 1 0. The hundreds digit of x would be 0. can someone please explain? thank you

Your problem is very simple : "x, y, and z are three-digit positive integers". x cannot be 1085, it must be \leq{999}

P.S: welcome to GmatClub! _________________

It is beyond a doubt that all our knowledge that begins with experience.

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
21 Aug 2013, 06:45

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Expert's post

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fozzzy wrote:

If x, y, and z are three-digit positive integers and if x = y + z, is the hundreds digit of x equal to the sum of the hundreds digits of y and z ?

(1) The tens digit of x is equal to the sum of the tens digits of y and z. (2) The units digit of x is equal to the sum of the units digits of y and z.

Is there an alternative approach for this problem?

The question basically asks whether there is a carry over 1 from the tens place to the hundreds place.

Consider the following examples: (i) 123 234 357

Here when we add the tens digits 2 and 3 there is no carry over 1 from the tens place to the hundreds place, thus the hundreds digit of x (3) is equal to the sum of the hundreds digits of y (1) and z (2).

(ii) 153 147 300

Here when we add the tens digits 5 and 4 and carry over 1 from the units place, we get 10, so we have carry over 1 from the tens place to the hundreds place, thus the hundreds digit of x (3) does NOT equal to the sum of the hundreds digits of y (1) and z (1).

The first statement implies that there is no carry over 1 from the tens place to the hundreds place, thus the hundreds digit of x is equal to the sum of the hundreds digits of y and z. Sufficient.

The second statement does not provide us with sufficient information about carry over 1 from the tens place to the hundreds place.

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
19 Jan 2014, 09:28

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Expert's post

Abheek wrote:

For Statement I my problem pertains to the fact that the ten's digit of x will be expressed as ten's digit of y + ten's digit of z. But if y=190 ,z=190 then x =380 the 1 does carry over from the ten's digit. Although the ten's digit of x is the sum of ten's digit of y and z.

Please Elaborate

The tens digit of y is 9 and the tens digit of z is 9 --> 9+9=18 not 8.

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
18 Sep 2012, 10:04

conty911 wrote:

If x, y, and z are three-digit positive integers and if x = y + z, is the hundreds digit of x equal to the sum of the hundreds digits of y and z ?

(1) The tens digit of x is equal to the sum of the tens digits of y and z. (2) The units digit of x is equal to the sum of the units digits of y and z.

Is it safe to conclude that the place value of an integer number (represented as a sum of different integers), depends upon only the preceding place value of integers being summed up?

for eg: x=1000a+100b+10c+1d y=1000e+100f+10g+1h z=1000l+100m+10n+1p if z=x+y then

is l only dependent upon value of b and f or some other parameters also??

Question is demanding 100 digit of Y + 100 digit of Z is equal to 100 digit of X, means there will not be any carryover from the sum of tens digit of Y and Z. therefore from Option 1, sum of tens digit of Y and Z equal to of X means there will not be any carryforward from here to 100 digit of Y and Z. therefore option 1 is sufficient to answer. Option 2 unit digit sum is equal, will not give any indication whether tens digit will not carryforward any to hundered. therefore this is not sufficient.

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
18 Sep 2012, 20:13

The concern here is the sum of the tenth digit might have a carryover, so the sum of the hundredth digit on Y & Z might not be equal to X's hundredth digit. So A is the right answer.

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
14 Jan 2013, 01:52

abhishekkpv wrote:

Let x= a b c y = d e f z= g h i

x= y+z

1 --> b= e+h which in turn implies c=f+i and so a=d+g (and this implies there is no carry forward in the addition of units and tens place digit of the two numbers)

2--> c=f+i which does not tell us if b= e+h(as there could be a carry forward bcos of this addition to the hundred place)

and so the answer is A

so this is sort of a number property? _________________

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
23 Feb 2013, 02:18

Let the 3 digit numbers be, x=ABC y=DEF z=GHI

Now, its given that DEF + GHI _____ ABC _____

Statement 1---- says that E+H=B. Substitute any digit for E and H, you will find that D+G must be equal to A. Sufficient Statement2.......says F+I=C. E and H can be anything and in turn D and G can be anything. Not sufficient. _________________

I've failed over and over and over again in my life and that is why I succeed--Michael Jordan Kudos drives a person to better himself every single time. So Pls give it generously Wont give up till i hit a 700+

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
13 Apr 2013, 10:23

abhishekkpv wrote:

Let x= a b c y = d e f z= g h i

x= y+z

1 --> b= e+h which in turn implies c=f+i and so a=d+g (and this implies there is no carry forward in the addition of units and tens place digit of the two numbers)

2--> c=f+i which does not tell us if b= e+h(as there could be a carry forward bcos of this addition to the hundred place)

and so the answer is A

my confusion is the following regarding (1). maybe i am not reading the question right, but assume the following:

y: 6 4 3 z: 4 4 2

x: 1 0 8 5

so, the tens digit of x is equal to the sum of the tens digit of y + z. however, the hundreds digit, 6 + 4 = 1 0. The hundreds digit of x would be 0. can someone please explain? thank you

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
13 Apr 2013, 10:29

Zarrolou wrote:

mokura wrote:

my confusion is the following regarding (1). maybe i am not reading the question right, but assume the following:

y: 6 4 3 z: 4 4 2

x: 1 0 8 5

so, the tens digit of x is equal to the sum of the tens digit of y + z. however, the hundreds digit, 6 + 4 = 1 0. The hundreds digit of x would be 0. can someone please explain? thank you

Your problem is very simple : "x, y, and z are three-digit positive integers". x cannot be 1085, it must be \leq{999}

P.S: welcome to GmatClub!

ouffff thanks so much for the quick reply and clarification. should re-read the question next time

Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
19 Jan 2014, 09:16

For Statement I my problem pertains to the fact that the ten's digit of x will be expressed as ten's digit of y + ten's digit of z. But if y=190 ,z=190 then x =380 the 1 does carry over from the ten's digit. Although the ten's digit of x is the sum of ten's digit of y and z.