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# If x ? -y, is (x-y)/(x+y)>1? 1) x>0 2) y<0

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Senior Manager
Joined: 08 Jun 2004
Posts: 498
Location: Europe
Followers: 1

Kudos [?]: 24 [0], given: 0

If x ? -y, is (x-y)/(x+y)>1? 1) x>0 2) y<0 [#permalink]  12 May 2006, 04:08
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If x ≠ -y, is (x-y)/(x+y)>1?

1) x>0
2) y<0
VP
Joined: 29 Dec 2005
Posts: 1348
Followers: 7

Kudos [?]: 37 [0], given: 0

Re: GMATPrep DS: ... >1? [#permalink]  12 May 2006, 05:47
M8 wrote:
If x ≠ -y, is (x-y)/(x+y)>1?

1) x>0
2) y<0

it says x-y or x+y cannot be 0.

i and ii, each, alone cannot answer the question. togather also not suff..

we know x = +ve and y = -ve.
suppose x = 5, y = -3, ok, it is true that (x-y)/(x+y)>1.
if x = 5, y = -8, ok, it is true that (x-y)/(x+y)<1.

so E.
Director
Joined: 16 Aug 2005
Posts: 946
Location: France
Followers: 1

Kudos [?]: 11 [0], given: 0

1) Lets assume x=5 y=2, then expression >1
Or x=5 and y=7, then expression <1
Not sufficient

2) Lets assume x=5 and y= -2, then expression >1
Or x=5 and y= -7, then expression <1
Hence not sufficient either.

Combining both, not sufficient either as examples in (2) meets both requirements of (1) and (2).
Hence E
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