chiragr wrote:

E

X+Y # 0

is x-y/x+y>1

Let's analyze different scenerio,

1) x+, y+

2) x-, y-

3) x+, y-

4) x-, y+

for (1) and (2) |x-y|<|x+y| => |x-y|/|x+y| < 1 it can be positive or negative depending on x>y or x<y

Look at example:

for (1)

(1, 2) =x-y/x+y = -1/3

(2, 1) =x-y/x+y = 1/3

for (2)

(-1, -2) =x-y/x+y = -1/3

(-2, -1) =x-y/x+y = 1/3

For (3) and (4) |x-y|>|x+y| => |x-y|/|x+y| > 1

if x+ and y-

(1,-2) =x-y/x+y = -3

(2,-1) =x-y/x+y = +3

if x- and y+

(-1,2) =x-y/x+y = -3

(-2,1) =x-y/x+y = 3

A) says x>0 does not tell us anything about Y insufficient

B) says y<0 does not tell us anything about X insufficient

togather x+ and y- scnerio 3, it can be positve or negative so insufficient!

Hence E

Thats great explanation...thanks Chirag and hass_mba

How long did it take you guys to do it?

I couldn't do this on the test due to time constraints and got it wrong...

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I believe its yogurt!