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1) insuff. 4 cases. a)y>0 and y<x answer is yes b)y>0 and y>x answer is yes c)y<0 and absolute value y>x answer is yes d)y<0 and absolute value y<x answer is no 2)insuff 4 cases a and b is like the above where is x>0 and answer is yes c)x<0 and y<x answer is yes d)x<0 and y>x answer is no
together x>0 and y<0 insuff depends on the comparison between the absolute value of y and x.
Re: Is (x-y)/ (x+y) < 1 1) x > 0 2) y < 0 [#permalink]
09 Oct 2013, 07:53
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